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3 years ago

Simplify i^15. (imaginary numbers to the 15th power)

Mathematics

1 answer:

dlinn [17]3 years ago

3 0

I x i x i x i x i x i x i x i x i x i x i x i x i x i x i

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A single box of thumb tacks weighed 3 1

emmasim [6.3K]

$3 \frac{1}{2} *4 \frac{1}{7} = \frac{7}{2} * \frac{29}{7} = \frac{29}{2} = 14\frac{1}{2} =14.5$

5 0

3 years ago

Please help I am struggling

likoan [24]

☆ The relation between x and y is y = a cos x° +b 

Taking 1st condition from the table .

→ x = 0 and y = 9

→ y = a + cos 0° + b

→ 9 = a + cos 0° + b

☆ We know that cos 0° = 1

→ 9 = a(1) + b

<h3>→ a + b = 9. equation 1st </h3>

Now taking other condition

→ x = 90° and y = 1

→ y = a cos 90° + b

→ 1 = a cos 90° + b

☆ We know that cos 90° is 0

→ 1 = a(0) + b

Putting the value of b in equation 1st . 

→ 9 = a + 1

→ a = 8 . 

Now taking the value of x according to the question .

☆ x = 45 °

→ y = 8 ( cos 45°) + 1

☆ We know that cos 45° is 1/√2

→ y = 8(1/√2) + 1

→ 8 = 4×√2×√2

So the answer is 4√2+1 

4 0

3 years ago

what is 10 + 10 + 10 + 10 + 10 + 10 + 10 + 10 + 10 + 10 + 10 + 12 + 10 + 1 + 8 + 6 + 5 + 8 + 1 + 16 + 84 + 6 + 10 + 10 + 10 + 10

Vanyuwa [196]

Answer:

317

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Suppose you pay $1.00 to roll a fair die with the understanding you will get $3.00 back rolling a 4 or a 2, and nothing otherwis

Evgesh-ka [11]

On the presumption that it is a cubic die, on average you will not gain nor lose any money. Out of the six faces, 1/3 of them are a 5 or a 2. So 1/3 of the time, you will gain 3$, but will lose 1$ from the initial payment. 1/3 of 3$ is 1$, so on average, you will gain 1$, while losing 1$.
Another way of looking at it is to take the possible out comes, and add the gains/loses, and you will come up with 0$.
1.9K views
Related Questions (More Answers Below)

6 0

3 years ago

What is the answer i'll give brainly

egoroff_w [7]

Answer:

c = -3

Step-by-step explanation:

Multiply all terms by the same value to eliminate fraction denominators

$4(-2)=4*\frac{-c-11}{4}$