Your answer should be B!
I hope this helped!
Answer:
[D] ![\displaystyle \lim_{h \to 0} \frac{[5(x + h)^2 - 2(x + h)] - (5x^2 - 2x)}{h}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Clim_%7Bh%20%5Cto%200%7D%20%5Cfrac%7B%5B5%28x%20%2B%20h%29%5E2%20-%202%28x%20%2B%20h%29%5D%20-%20%285x%5E2%20-%202x%29%7D%7Bh%7D)
General Formulas and Concepts:
<u>Calculus</u>
Limits
Derivatives
Definition of a Derivative: ![\displaystyle f'(x)= \lim_{h \to 0} \frac{f(x+h)-f(x)}{h}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f%27%28x%29%3D%20%5Clim_%7Bh%20%5Cto%200%7D%20%5Cfrac%7Bf%28x%2Bh%29-f%28x%29%7D%7Bh%7D)
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
![\displaystyle f(x) = 5x^2 - 2x](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f%28x%29%20%3D%205x%5E2%20-%202x)
<u>Step 2: Differentiate</u>
- Substitute in function [Definition of a Derivative]:
![\displaystyle f'(x)= \lim_{h \to 0} \frac{[5(x + h)^2 - 2(x + h)] - (5x^2 - 2x)}{h}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f%27%28x%29%3D%20%5Clim_%7Bh%20%5Cto%200%7D%20%5Cfrac%7B%5B5%28x%20%2B%20h%29%5E2%20-%202%28x%20%2B%20h%29%5D%20-%20%285x%5E2%20-%202x%29%7D%7Bh%7D)
Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Derivatives
Book: College Calculus 10e
Answer: No solution
x(5-2)(2-2)=12
x(3)(0)=12
Since its times by 0 the x goes away and it is
0=12
No solution
Answer:
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Step-by-step explanation:
The voloum is 8 cubic cm.
Answer:
Step-by-step explanation:
ok so first u have to multiply 9x5 which is 45 and put it under the 5
then u multiply 3x5 which is 15 and u put it under the 5 next to the 3
u do the samething over and over, is just basically time tables