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irga5000 [103]
4 years ago
14

Factorize: (2a+3b) the whole square-16c square

Mathematics
2 answers:
netineya [11]4 years ago
4 0

Answer:

Step-by-step explanation:

hello :

(2a+3b)² - (16c)² = [(2a+3b) - 16c]×[(2a+3b) + 16c]

                         =  [2a + 3b - 16c]×[2a + 3b + 16c]

by identity : x²- y² = (x-y)(x+y) when  x= 2a+3b   and  y = 16c

Charra [1.4K]4 years ago
3 0

Answer:

<h2>(2a+3b)² - (16c)² = (2a + 3b - 16c)×(2a + 3b + 16c)</h2>

Step-by-step explanation:

(2a+3b)² - (16c)² = [(2a+3b) - 16c]×[(2a+3b) + 16c]

                          =  [2a + 3b - 16c]×[2a + 3b + 16c]

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