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Alex_Xolod [135]
3 years ago
5

Line j passes through the points (-5,-2)

Mathematics
2 answers:
Lisa [10]3 years ago
7 0

Answer:

y=-1x+1

Step-by-step explanation:

svetoff [14.1K]3 years ago
5 0

Answer:

y = - 5/3x + 1

Step-by-step explanation:

Slope of line j = (-2-4)/(-5-5)

Slope = -6/-10 = 3/5

Slope of the perpendicular line k: -5/3

Point of line k: (-3,6)

y-intercept of line k = 6 - (-5/3)(-3) = 6 - 5 = 1

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LekaFEV [45]
The zero product property tells us that if the product of two or more factors is zero, then each one of these factors CAN be zero.

For more context let's look at the first equation in the problem that we can apply this to: (x-3)(x+4)=0

Through zero property we know that the factor (x-3) can be equal to zero as well as (x+4). This is because, even if only one of them is zero, the product will immediately be zero.

The zero product property is best applied to factorable quadratic equations in this case.

Another factorable equation would be 2x^{2}+6x=0 since we can factor out 2x and end up with 2x(x+3)=0. Now we'll end up with two factors, 2x and (x+3), which we can apply the zero product property to.

The rest of the options are not factorable thus the zero product property won't apply to them.
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4 years ago
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3 years ago
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ch4aika [34]
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3 years ago
D is the midpoint of CE. If CD= 2x+10 and DE =3x-18, find x and CE<br><br> x=<br> CE=
Veseljchak [2.6K]

Answer:

<h2>x = 28</h2><h2>CE = 132</h2><h2 />

Step-by-step explanation:

|<------------- CE -------------------->|

C-------------------D-------------------E

       2x + 10              3x - 18

2x + 10 = 3x - 18

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Answer:

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Step-by-step explanation:

elimination method

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