At first find the area of rectangle:
(x + 4)*(x + 1) = x^2 + 5x + 4
Then find the area of triangle:
![\frac{(x+1)(x-3)}{2} = \frac{x^2-2x-3}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%28x%2B1%29%28x-3%29%7D%7B2%7D%20%3D%20%20%5Cfrac%7Bx%5E2-2x-3%7D%7B2%7D%20)
Then you must do like this
Area of rectangle - Area of triangle = Area of the shaded
x^2+5x+4 - (
![\frac{x^2-2x-3}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%5E2-2x-3%7D%7B2%7D%20)
)
All you need to know is what irrational means and then you can decide is the width is a fraction a whole number or a decimal etc
Hello,
I would love to answer but there is no screenshot to see!
Answer:
-17
Step-by-step explanation:
LCM=8
3/4(1/4x+8)-(1/2x+2)=3/8(4-x)-1/4x
6(
Hello there!
(a + b)² = a² + 2ab + b²
= a² + b² + 2ab
= 16 + 2(8)
= 16 + 16
= 32
As always, it is my pleasure to help students like you!