The parents both have large teeth, which is dominant. Two dominants make another dominant, so the baby will have large teeth.
Answer:
The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the minimum weight for a passenger who outweighs at least 90% of the other passengers?
90th percentile
The 90th percentile is X when Z has a pvalue of 0.9. So it is X when Z = 1.28. So
The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds
Answer:
85 parking spaces
Step-by-step explanation:
Given that :
Parking spaces on floors :
Let first floor = x
Second floor = 2x
Third floor = 2x + 3
Total parking spaces = 428
THEREFORE ;
x + 2x + 2x + 3 = 428
5x + 3 = 428
5x = 428 - 3
5x = 425
x = 425 / 5
x = 85
Hence, there are 85 parking spaces on the first floor
Answer:
There are no values of x that makes the equation true. or in other words ( no solution)
Work out the top subtraction first:
3/9 - 8/12
= 1/3 - 2/3
= 1/3
and the bottom part:-
3/8 * 2 = 6/8 = 3/4
so now we divide -1/3 by 3/4
= -1/3 * 4/3 = -4/9