Let Kamil get x. Therefore Sean would get (x + 56).
Kamil and Sean are in the ratio: 3:5
That means: x : (x + 56) = 3 : 5
x / (x + 56) = 3/5
5*x = 3*(x + 56)
5x = 3*x + 3*56
5x = 3x + 168
5x - 3x = 168
2x = 168
x = 168 / 2
x = 84
Therefore Kamil had, x = 84, and Sean had (x + 56) = 84 + 56 = 140
Kamil had $84 and Sean had $140
Answer:
Step-by-step explanation:
5.27=3.40+.85x
1.87=.85x
2.2=x
Jessica’s mistake is that when isolating h from b, she multiplied b instead of dividing it on both sides. The new formula for h would be A/2b=h.
Now let’s solve. 23/2(6)=h
23/12
Approx. 1.91
Do you mean 7?
You need to multiply each like term differently ( 1. Coefficient, 2. M term, 3. N term, and 4. O term)
1. The coefficients are 4 and 7, and as you have already solved, that equals to 28.
2. The m terms are (m • m) because there is one m in (4mno) and one m in (mn). m • m would equal to m^2.
3. The n terms are (n • n^2 •n) because there is one n in (4mno), n^2 in (7n^2o^2), and one n in (mn). They would equal n^4.
4. The o term would stay as o^2 as there are not other o terms.
To piece it all together, your answer would be 28m^2n^4o^2, or 28 • m ^2 • n^4 • o^2.