Question

In an isosceles right triangle of the hypotenuse is 1 unit when are the other two sides?

Answer 1

Answer:

For any other isosceles triangle replace the 1 with the required value of the equal sides.

Example : Let the equal sides be 7, the hypotenuse will be 7√2 which is approximately 9.9.

Step-by-step explanation:

Brainliest would be appreciated.

Answer 2

Answer:the other sides are 1/√2 each

Step-by-step explanation:

in isosceles right triangle two sides are equal

Hypotenuse=1 the other two sides are equal

Let them two equal sides be y

From Pythagoras principle we get

(hypotenuse)^2=(opposite)^2+(adjacent)^2

1^2=y^2+y^2

1x1=2y^2

1=2y^2

Divide both sides by 2

1/2=2y^2/2

1/2=y^2

Take them square root of both sides

√(1/2)=√(y^2)

1/√2=y

y=1/√2

Therefore they other sides are 1/√2 each