Answer:
12 inches
Step-by-step explanation:
Raj tested his new flashlight by shinning it on his bedroom wall the beam of the light can be described by the equation (x^2-2x) + (y^2-4y) - 31=0. how many inches wide is the beam of light on the wall
Solution
Given:
(x^2-2x) + (y^2-4y) - 31=0
By completing the square
(x^2-2x) + (y^2-4y) - 31=0
(x^2-2x+1-1) + (y^2-4y+4-4)-31=0
(x-1)^2 -1 + (y-2)^2 - 4 - 31=0
(x-1)^2 + (y-2)^2 - 1 - 4 - 31=0
(x-1)^2 + (y-2)^2 - 36=0
(x-1)^2 + (y-2)^2=36
Writing the equation in the form: (x-h)^2+(y-k)^2=r^2
(x-1)^2+(y-2)^2=6^2
From the above, r=6
Where,
r=radius
how wide is the diameter ?
radius=6
Diameter= 2 × radius
=2×6
=12 inches
The weight is 62 and a half lb per cubic feet.
Answer:
x = -3/2 = -1.500
x = 7/3 = 2.333
Step-by-step explanation:
Answer:
the answer is 42.
Step-by-step explanation:
(8)(5)−8+(2)(5)
=42
Answer:
D
Step-by-step explanation:
--2x-2x-2x-2 = -16
2x (-2x-2x-2) = -16
-2x-2= 4
4x-2+8= 0
-16+-16+4+0 = -32+4
= -36