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Archy [21]
3 years ago
11

Solve for x given BD = 4x+3 and AE = 4x+8. Assume B is the midpoint of segment AC and D is the midpoint of segment CE.

Mathematics
1 answer:
wolverine [178]3 years ago
8 0

Answer: The fraction x = 1/2 or its equivalent decimal form x = 0.5

================================================

Work Shown:

AE = 2*(BD)

4x+8 = 2*(4x+3)

4x+8 = 8x+6

8-6 = 8x-4x

2 = 4x

4x = 2

x = 2/4

x = 1/2

x = 0.5

note: the first equation is set up basically saying that AE is twice that of BD; put another way, BD is half as long as AE. This is one property of midsegments. Another property is that AE and BD are parallel.

another note: if x = 0.5, then AE = 4*x+8 = 4*0.5+8 = 10 while BD = 4*x+3 = 4*0.5+3 = 5, showing that AE is indeed two times longer than BD.

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A researcher wishes to be 95% confident that her estimate of the true proportion of individuals who travel overseas is within 3%
andre [41]

Answer:  a) 683   b) 1067

Step-by-step explanation:

The confidence interval for population proportion is given by :-

p\pm z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}}

a) Given : Significance level :\alpha=1-0.95=0.05

Critical value : z_{\alpha/2}}=\pm1.96

Margin of error : E=0.03

Formula to calculate the sample size needed for interval estimate of population proportion :-

n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.2(0.8)(\dfrac{1.96}{0.03})^2=682.951111111\approx683

Hence, the required sample size would be 683 .

b) If no estimate of the sample proportion is available then the formula to calculate sample size will be :-

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Hence, the required sample size would be 1067 .

3 0
3 years ago
What is the radius of a circle with an area of 50.24 cubic inches? Use 3.14 for pi. Enter your answer in the box.
N76 [4]

Hope this helps you..!!!

Answer:

r=4

Step-by-step explanation:


Area of a circle is


A = pi* r^2


We know the area and 3.14 = pi


50.24 = 3.14 * r^2


Divide each side by 3.14


50.24/3.14 =3.14 /3.14 *r^2


16 = r^2


Take the square root of each side


sqrt(16) = sqrt(r^2)


4 =r





7 0
3 years ago
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