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3 years ago

Need help with my maths please ,having lol problem.

Mathematics

2 answers:

mihalych1998 [28]3 years ago

7 0

For every van there are 6 students 6x,(6 students,x is the number of vans)

Vesna [10]3 years ago

4 0

Below are a few ways to demonstrate some of the patterns in the graph.

Vans to students:
$\frac{1}{6}$
1:6
1 to 6

I hope this helps!

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What is 5.712g=in kg

mel-nik [20]

Answer:

5.712g in kg is<u><em> 0.0057Kilograms</em></u>

Step-by-step explanation:

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1 year ago

Read 2 more answers

If B is the midpoint of AC, AC=CD, AB=3x+4, AC=11x-17, and CE=49, find DE.

Luba_88 [7]

Answer:

Step-by-step explanation:

AB = 3x + 4 and AC which is twice of AB is equal to 11x - 17

2 (3x + 4) = 11x - 17

6x + 8 = 11x - 17

8 + 17 = 11x - 6x

25 = 5x

5 = x

AC = CD = 11x - 17 ➡ 11×5 - 17 = 38

CD = 38 and DE = 49 - 38 = 11

6 0

2 years ago

Ross chose a card at random from a deck of 52 cards. Ross replaced the card and then chose a second card. What is the probabilit

DaniilM [7]

Answer:

$\frac{1}{208}$

Step-by-step explanation:

We have been given that Ross chose a card at random from a deck of 52 cards. Ross replaced the card and then chose a second card.

Let us find probability of getting a club.

$\text{ Probability of getting a club}=\frac{13}{52} =\frac{1}{4}$

Now let us find probability of getting the ace of spades.

$\text{ Probability of getting ace of spades}=\frac{1}{52}$

Now let us multiply these to find probability of getting a club and ace of spades.

$\text{ Probability of getting a club and then ace of spades}=\frac{1}{4}*\frac{1}{52}=\frac{1}{208}$

Therefore, probability of getting a club and then the ace of spades $\frac{1}{208}$ .

8 0

3 years ago

QUIL - Level G p) The total cost of a pizza and 3 drinks is $19. The price of the pizza is $10 and each drink is the same price,

garri49 [273]

Answer:

Step-by-step explanation:

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2 years ago

3=g/-4-5 ((for 25 points))

Ymorist [56]

Answer:

3=g/-4 -5

3+5=g/-4

8= g/-4

8x(-4)=g

g=-32

Step-by-step explanation:

7 0

2 years ago