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kolezko [41]
3 years ago
8

Sin(a+b).cos(a-b) = sinacosa + sinbcosb

Mathematics
1 answer:
Rainbow [258]3 years ago
4 0
Sin (A + B) = sin A cos B + cos A Sin B 
<span>Cos (A - B) = cos A cos B + sin A sin B </span>

<span>=> (SinACosB+ CosASinB) (CosACosB +SinASinB) </span>

<span>=>SinACosACos^2B+Sin^2ACosBSinB+Cos^2A... </span>

<span>=>SinACosA(Cos^2B+Sin^2B) +SinBCosB(Sin^2A+Cos^2A) </span>
<span>we know that Sin^2+Cos^2=1 </span>
<span>=>SinACosA(1)+SinBCosB(1) </span>
<span>=SinACosA+SinBCosB </span>
<span>Proved 

</span>
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