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3 years ago

8

Sin(a+b).cos(a-b) = sinacosa + sinbcosb

1 answer:

Rainbow [258]3 years ago

4 0

Sin (A + B) = sin A cos B + cos A Sin B
<span>Cos (A - B) = cos A cos B + sin A sin B </span>

<span>=> (SinACosB+ CosASinB) (CosACosB +SinASinB) </span>

<span>=>SinACosACos^2B+Sin^2ACosBSinB+Cos^2A... </span>

<span>=>SinACosA(Cos^2B+Sin^2B) +SinBCosB(Sin^2A+Cos^2A) </span>
<span>we know that Sin^2+Cos^2=1 </span>
<span>=>SinACosA(1)+SinBCosB(1) </span>
<span>=SinACosA+SinBCosB </span>
<span>Proved

</span>

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Step-by-step explanation:

The computation is shown below:

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the volume would be equivalent to the

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