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kolezko [41]
3 years ago
8

Sin(a+b).cos(a-b) = sinacosa + sinbcosb

Mathematics
1 answer:
Rainbow [258]3 years ago
4 0
Sin (A + B) = sin A cos B + cos A Sin B 
<span>Cos (A - B) = cos A cos B + sin A sin B </span>

<span>=> (SinACosB+ CosASinB) (CosACosB +SinASinB) </span>

<span>=>SinACosACos^2B+Sin^2ACosBSinB+Cos^2A... </span>

<span>=>SinACosA(Cos^2B+Sin^2B) +SinBCosB(Sin^2A+Cos^2A) </span>
<span>we know that Sin^2+Cos^2=1 </span>
<span>=>SinACosA(1)+SinBCosB(1) </span>
<span>=SinACosA+SinBCosB </span>
<span>Proved 

</span>
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(9 x 10) + (4 x 0.1)<br> how is this temperature in degrees fahrenheit written as a numeral?
mash [69]

Answer:

360°F

Step-by-step explanation:

When you multiply the numerals in the brackets . The first set of brackets is 90 then the second is 4.0 then multiply them and you will get 360.0°F

3 0
3 years ago
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A small business assumes that the demand function for one of its new products can be modeled by p = Cekx. When p = $40, x = 1000
Maru [420]

Answer:

C= 82.1116

k=-0.0007192

Step-by-step explanation:

p=Ce^{kx}\\40=Ce^{k1000}\\30=Ce^{k1400}\\

Applying logarithmic properties yields in the following linear system:

ln(40) = ln(C) + 1000k\\ln(30) = ln(C) + 1400k

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ln(40) = ln(C) + 1000k\\ln(30) = ln(C) + 1400k\\400 k = ln(30)-ln(40)\\k=-0.0007192

Solving for C:

40=Ce^{-0.0007192*1000}\\C= \frac{40}{e^{-0.0007192*1000}}\\C=82.1116

C= 82.1116

k=-0.0007192

6 0
3 years ago
The distance from Neptune to Mars is 4.272\times 10^{9}4.272×10 9 kilometers. How long would it take a rocket, traveling at 4.8\
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The time taken is 8.9 * 10^4hrs&#10;&#10;&#10;

<h3>Distances</h3>

Given the following information:

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  • Time is taken = 4.8\times 10^{4}km/hr

Get the time taken:

Time  = Distance/Speed

Time = \frac{4.272\times10^9}{4.8\times 10^4}

Time = 0.89 * 10^5

Time = 8.9 * 10^4hrs

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Learn more on distance here: brainly.com/question/4931057

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B

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3 years ago
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