Plz help brainiest to whoever right

Mathematics

1 answer:

nadya68 [22]2 years ago

6 0

Answer:

They add up to equal 90 degrees.

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Hi howww r uuuu allll

stich3 [128]

Answer:

good now that i get free points!

Step-by-step explanation:

8 0

3 years ago

Simplify and Evaluate

zalisa [80]

$\dfrac{2^{-1} + 5^{-1}}{10^{-1} - 5^{-2}} =$

$= \dfrac{\frac{1}{2} + \frac{1}{5}}{\frac{1}{10} - \frac{1}{5^2}}$

$=\dfrac{\frac{1}{2} + \frac{1}{5}}{\frac{1}{10} - \frac{1}{25}}$

$=\dfrac{\frac{5}{10} + \frac{2}{10}}{\frac{5}{50} - \frac{2}{50}}$

$=\dfrac{\frac{7}{10}}{\frac{3}{50}}$

$= \frac{7}{10} \times \frac{50}{3}$

$= \frac{7}{1} \times \frac{5}{3}$

$= \frac{35}{3}$

4 0

3 years ago

A plane flew 360km in 3 hrs when flying with the wind.With no change in the wind,the return trip took 4 hrs.Find the speed of th

morpeh [17]

Speed of the plane: 250 mph
Speed of the wind: 50 mph
Explanation:
Let p = the speed of the plane
and w = the speed of the wind
It takes the plane 3 hours to go 600 miles when against the headwind and 2 hours to go 600 miles with the headwind. So we set up a system of equations.
600
m
i
3
h
r
=
p
−
w
600
m
i
2
h
r
=
p
+
w
Solving for the left sides we get:
200mph = p - w
300mph = p + w
Now solve for one variable in either equation. I'll solve for x in the first equation:
200mph = p - w
Add w to both sides:
p = 200mph + w
Now we can substitute the x that we found in the first equation into the second equation so we can solve for w:
300mph = (200mph + w) + w
Combine like terms:
300mph = 200mph + 2w
Subtract 200mph on both sides:
100mph = 2w
Divide by 2:
50mph = w
So the speed of the wind is 50mph.
Now plug the value we just found back in to either equation to find the speed of the plane, I'll plug it into the first equation:
200mph = p - 50mph
Add 50mph on both sides:
250mph = p
So the speed of the plane in still air is 250mph.

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2 years ago

Find the length of AB when A(-4,1) and B(3,-1). Round to the nearest tenth (one decimal place) if necessary.

ivanzaharov [21]

Answer:

7.3 units is the answer rounded

8 0

3 years ago

Clearly mark on the coordinate plane the location of the ordered pairs and

ladessa [460]

Answer:

Point $J(4,0)$ lies on $x-$ axis and point $M(-2,-3)$ lies quadrant III.