3×5 (64-65)= just want to test if it works

What is the Volume of the prism?

Andru [333]

Answer:

296.4cm

Step-by-step explanation:

you do 9.5cm x 5.2cm x 6cm = 296.4cm

8 0

2 years ago

If angle LMPis 11 degrees more than angle NMP and angle NML is 137 find each measure.

OLEGan [10]

Answer:

angle NMP = 63°

angle LMP = 74°

Step-by-step explanation:

Let angle NMP be x° . It's given that angle LMP is 11° more than angle NMP. So, angle LMP = x° + 11°

But angle NML = 137°.

So,

angle NMP + angle LMP = 137°

=> x° + x° + 11° = 137°

=> 2x° + 11° = 137°

=> 2x° = 137° - 11°

= 126°

=> x° = 126/2 = 63°

angle NMP = 63°

angle LMP = 63 + 11 = 74°

7 0

4 years ago

Read 2 more answers

A simple random sample of size n=14 is obtained from a population with μ=64 and σ=19.

madam [21]

Answer:

a) A. The population must be normally distributed

b) P(X < 68.2) = 0.7967

c) P(X ≥ 65.6) = 0.3745

Step-by-step explanation:

a) The population is normally distributed having a mean ( $\mu_x$ ) = 64 and a standard deviation ( $\sigma_x$ ) = $\frac{19}{\sqrt{14} }$

b) P(X < 68.2)

First me need to calculate the z score (z). This is given by the equation:

$z=\frac{x-\mu_x}{\sigma_x}$ but μ=64 and σ=19 and n=14, $\mu_x=\mu=64$ and $\sigma_x=\frac{ \sigma}{\sqrt{n} }=\frac{19}{\sqrt{14} }$

Therefore: $z=\frac{68.2-64}{\frac{19}{\sqrt{14} } }=0.83$

From z table, P(X < 68.2) = P(z < 0.83) = 0.7967

P(X < 68.2) = 0.7967

c) P(X ≥ 65.6)

First me need to calculate the z score (z). This is given by the equation:

$z=\frac{x-\mu_x}{\sigma_x}$

Therefore: $z=\frac{65.6-64}{\frac{19}{\sqrt{14} } }=0.32$

From z table, P(X ≥ 65.6) = P(z ≥ 0.32) = 1 - P(z < 0.32) = 1 - 0.6255 = 0.3745

P(X ≥ 65.6) = 0.3745

P(X < 68.2) = 0.7967

5 0

3 years ago

Write the recurring decimal 0.05 as a fraction in its simplest form

lidiya [134]

Answer:

1/20

Step-by-step explanation:

Step 1: Write the given number as the numerator and place 1 in the denominator right below the decimal point followed by the number of zeros required accordingly.

In this case, 0.05 has two numbers after the decimal, so, we place 100 in the denominator and remove the decimal point. This will make it 5/100

Step 2: Then, this fraction can be simplified. 5/100 = 1/20

Thus, 0.05 as a fraction is written as 1/20

6 0

3 years ago

Read 2 more answers

The length and width of a rectangle are measured as 55 cm and 49 cm, respectively, with an error in measurement of at most 0.1 c

valentina_108 [34]

Answer:

The maximum error in the calculated area of the rectangle is $10.4 \:cm^2$

Step-by-step explanation:

The area of a rectangle with length $L$ and width $W$ is $A= L\cdot W$ so the differential of <em>A</em> is

$dA=\frac{\partial A}{\partial L} \Delta L+\frac{\partial A}{\partial W} \Delta W$

$\frac{\partial A}{\partial L} = W\\\frac{\partial A}{\partial W}=L$ so

$dA=W\Delta L+L \Delta W$

We know that each error is at most 0.1 cm, we have $|\Delta L|\leq 0.1$ , $|\Delta W|\leq 0.1$ . To find the maximum error in the calculated area of the rectangle we take $\Delta L = 0.1$ , $\Delta W = 0.1$ and $L=55$ , $W=49$ . This gives

$dA=49\cdot 0.1+55 \cdot 0.1$

$dA=10.4$

Thus the maximum error in the calculated area of the rectangle is $10.4 \:cm^2$

4 0

3 years ago