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4 years ago

What is the length of segment AB?

Mathematics

2 answers:

allochka39001 [22]4 years ago

4 0

The answer to this question is 8

Levart [38]4 years ago

4 0

Answer:

The length of segment AB is 5.

Step-by-step explanation:

If you use the Pythagorean theorem, you would find that the answer is 5.

One side of the triangle is a length of 4. The last side is a length of 3.

a^2+b^2=c^2

4^2+3^2=c^2

16+9=25

The square root of 25 is 5.

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Answer:

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Step-by-step explanation:

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3 years ago

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All 6 members of a family work. Their hourly wages (in dollars) are the following.37, 38, 39, 40, 39, 11Assuming that these wage

tiny-mole [99]

We have a sample that in fact represents the population.

We have to calculate the standard deviation of this population.

The difference between the standard deviation of a population comparing it to the calculation of the standard deviation of a sample is that we divide by the population side n instead of (n-1).

We have to start by calculating the mean of the population first:

$\begin{gathered} \mu=\dfrac{1}{n}\sum ^n_{i=1}\, x_i \\ \mu=\dfrac{1}{6}(37+38+39+40+39+11) \\ \mu=\dfrac{204}{6} \\ \mu=34 \end{gathered}$

Now, we can calculate the standard deviation as:

$\sigma=\sqrt[]{\dfrac{1}{n}\sum^n_{i=1}\, (x_i-\mu)^2}$ $\begin{gathered} \sigma=\sqrt[]{\dfrac{1}{6}((37-34)^2+(38-34)^2+(39-34)^2+(40-34)^2+(39-34)^2+(11-34)^2)} \\ \sigma=\sqrt[]{\frac{1}{6}(3^2+4^2+5^2+6^2+5^2+(-23)^2)} \\ \sigma=\sqrt[]{\frac{1}{6}(9+16+25+36+25+529)} \\ \sigma=\sqrt[]{\frac{1}{6}(640)} \\ \sigma\approx\sqrt[]{106.67} \\ \sigma\approx10.33 \end{gathered}$

Answer: the standard deviation of this population is approximately 10.33

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