It would be a 50/50 chance that all of them would be girls
Answer:
R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]
Step-by-step explanation:
Squaring both sides of equation:
I^2 = (ER)^2/(R^2 + (WL)^2)
<=>(ER)^2 = (I^2)*(R^2 + (WL)^2)
<=>(ER)^2 - (IR)^2 = (IWL)^2
<=> R^2(E^2 - I^2) = (IWL)^2
<=> R^2 = (IWL)^2/(E^2 - I^2)
<=> R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]
Hope this helps!
Given that the distance between two lines in the measurement instrument is 0.01m, the maximum error should be 0.01m/2 = 0.005 m.
If you do a good work, the real measure is 1.20m +/- 0.005m, this is between 1.195 and 1.205.
Assuming you have some angle measures, you could use the
Law of Sines to solve for the missing side lengths, which states that,

,
where a, b, and c correspond to the given sides you have, and A, B, and C represent the angles you have.
In this scenario, you would have to have the values for c (which we do), and have the angle measure of C. In addition, we would also need an angle measure that is either A or B.
Hope this helps a bit!
:)
Answer: It would be the number 1 since they all cancel each other out
Step-by-step explanation: