To determine whether our equations are balanced, we must write the elements on the products side and also the reactants side. If the amount of the elements (coefficients and subscripts) are equal on both sides, we have a balanced equation.
Lets try (A)
2NaCl + H₂SO₄ → HCl + NaSO₄
Na=2 Na=1
Cl=2 Cl=1
H=2 H=1
Na=2 Na=1
S=1 S=1
O=4 O=4
Most of the elements here are not equal for both sides, therefore, A is not the answer.
Lets try (B)
2Na + S → 2NaS
Na=2 Na=2
S=1 S=2
This is a wrong answer because S is not equal on both sides. B is a wrong answer.
Lets try (C)
KOH + H2SO4 → KHSO4 + H2O
K=1 K=1
O= 1 O=1
H=1 H=1
H=2 H=2
S=1 S=1
O=4 O=4
THIS IS A BALANCED EQUATION!!!! ALL ELEMENTS ARE EQUAL ON BOTH SIDES!!!
Since we already know that C is our answer, we have no need to check D. Also, D is incorrect because N has 1 on reactants side, and 2 on the other. Therefore, we automatically know that D is wrong.
FINAL ANSWER: C IS OUR ANSWER, IT IS A BALANCED EQUATION. :)
<span>4.3065 g
First, lookup the atomic weights of all the elements involved.
Atomic weight of Calcium = 40.078
Atomic weight of Carbon = 12.0107
Atomic weight of Hydrogen = 1.00794
Atomic weight of Oxygen = 15.999
Atomic weight of Sulfur = 32.065
Now calculate the molar masses of the reactants and product
Molar mass H2SO4 = 2 * 1.00794 + 32.065 + 4 * 15.999
= 98.07688 g/mol
Molar mass CaCO3 = 40.078 + 12.0107 + 3 * 15.999
= 100.0857 g/mol
Molar mass CaSO4 = 40.078 + 32.065 + 4 * 15.999
= 136.139 g/mol
The balanced reaction for H2SO4 with CaCO3 is
CaCO3 + H2SO4 ==> CaSO4 + H2O + CO2
So it takes 1 mole each of CaCO3 and H2SO4 to produce 1 mole of CaSO4. Let's see how many moles of CaCO3 and H2SO4 we have.
CaCO3: 3.1660 g / 100.0857 g/mol = 0.031632891 mol
H2SO4: 3.2900g / 98.07688 g/mol = 0.033545113 mol
We have a slight excess of H2SO4, so the amount of CaCO3 is the limiting reactant and we should have 0.031632891 moles of product. To determine its mass, multiply the number of moles by the molar mass computed earlier.
0.031632891 mol * 136.139 g/mol = 4.306470148 g
Since we have 5 significant figures in our data, round the result to 5 figures, giving 4.3065 g</span>
Potential energy<span> is the </span>energy<span> that is stored in an object due to its position relative to some zero position. It is calculated by the expression as follows:
PE = mgh
PE = 25 (9.8) (3)
PE = 735 J
Hope this answers the question. Have a nice day.</span>
Answer:hey man am sorry but have you tried to search it up
Explanation:
Answer:
<h2>both of them</h2>
Explanation:
<h3>I hope it's helpful for you ✌</h3>