A soap bubble has a diameter of 3 cm. what is the surface area in square cm

4. REINFORCE A recipe for lemonade call for 3 lemons for every 2 cups of water.

Oksanka [162]

Answer:

PLZ MARK BRAINLIEST!

The answer is below...Can you farther explain on the part "Find at least one ratio where one of the quan

a fraction or decimal."

Step-by-step explanation:

LEMONS . CUPS

3 : 2 . 3/2

6 : 4 . 6/4

9 : 6 9/6

12 : 8 . 12/8

15 : 10 . 15/10

5 0

3 years ago

What is an angle that is adjacent to<br> CED?

devlian [24]

I think BEA is adjacent to it

8 0

3 years ago

Hey i need help (winner gets crowned brainlyest)

Alenkinab [10]

Answer:

Step-by-step explanation:

13) x⁴-12x² +36

(a-b)² = a²-2ab+b²

a = x² ; b = 6

(x²)² - 2 * x² * 6 + 6² = (x² - 6)²

14) w⁴- 14w² - 32 = w⁴+ 2w² - 16w² - 32 = w² (w² + 2) - 16 (w²+2)

= (w² + 2) (w² -16 )

15) k³ + 7k² - 44k = k ( k² + 7k -44) = k ( k+11 ) ( k-4 )

16) 2a³ +28a²+96a =2a(a²+14a+48) = 2a(a+6)(a+8)

17) -x³ +4x² +21x = (-x) ( x² - 4x - 21) = (-x)(x-7)(x+3)

18) m⁶ - 7m⁴ -18m² = m² ( m⁴-7m²-18) = m² (m²-9)(m²+9)

= m² (m+1) (m-1)(m²+9)

19) 9y⁶ +6y⁴ + y²= y² ( 9y⁴+6y²+1) = y² (3y²+1)²

20) 8c⁴+10c² -3 = (4c +1)(2c-3)

3 0

3 years ago

A random sample of n = 40 observations from a quantitative population produced a mean x = 2.2 and a standard deviation s = 0.29.

zmey [24]

Answer:

$t=\frac{2.2-2.1}{\frac{0.29}{\sqrt{40}}}=2.18$

$df=n-1=40-1=39$

Since is a one side test the p value would be:

$p_v =P(t_{(39)}>2.18)=0.0177$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and then the population mes seems to be higher than 2.1 at 5% of significance

Step-by-step explanation:

Data given and notation

$\bar X=2.2$ represent the sample mean

$s=0.29$ represent the sample standard deviation

$n=40$ sample size

$\mu_o =2.1$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 2,1, the system of hypothesis would be:

Null hypothesis: $\mu \leq 2.1$

Alternative hypothesis: $\mu > 2.1$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{2.2-2.1}{\frac{0.29}{\sqrt{40}}}=2.18$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=40-1=39$

Since is a one side test the p value would be:

$p_v =P(t_{(39)}>2.18)=0.0177$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and then the population mes seems to be higher than 2.1 at 5% of significance

7 0

4 years ago

Number 2 to 4 I don’t understand it.

Natalka [10]

All estimating problems make the assumption you are familar with your math facts, addition and multiplication. Since students normally memorize multiplication facts for single-digit numbers, any problem that can be simplified to single-digit numbers is easily worked.

2. You are asked to estimate 47.99 times 0.6. The problem statement suggests you do this by multiplying 50 times 0.6. That product is the same as 5 × 6, which is a math fact you have memorized. You know this because
.. 50 × 0.6 = (5 × 10) × (6 × 1/10)
.. = (5 × 6) × (10 ×1/10) . . . . . . . . . . . by the associative property of multiplication
.. = 30 × 1
.. = 30

3. You have not provided any clue as to the procedure reviewed in the lesson. Using a calculator,
.. 47.99 × 0.6 = 28.79 . . . . . . rounded to cents

4. You have to decide if knowing the price is near $30 is sufficient information, or whether you need to know it is precisely $28.79. In my opinion, knowing it is near $30 is good enough, unless I'm having to count pennies for any of several possible reasons.

5 0

3 years ago