Question

HELP i know this is simple but i cant seem to find the correct equation

Answer 1

Answer:  g(x) = (-2/3)*x^2

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Work Shown:

f(x) = x^2

g(x) = a*f(x) for some constant 'a' since g(x) is a scaled version of f(x).

The value of 'a' vertically stretches f(x) upward if a > 0

If 'a' is negative, then we have a reflection going on as shown in the diagram.

We want (x,y) = (3,-6) to be on the graph of g(x). This means g(3) = -6

If we plugged x = 3 into f(x), we get

f(x) = x^2

f(3) = 3^2

f(3) = 9

So,

g(x) = a*f(x)

g(3) = a*f(3) ... replace x with 3

g(3) = a*9 ... replace f(3) with 9 since f(3) = 9

-6 = a*9 ... replace g(3) with -6 since g(-3) = -6

9a = -6

a = -6/9

a = -2/3

Therefore, this means

g(x) = a*f(x)

g(x) = (-2/3)*f(x)

g(x) = (-2/3)*x^2