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Evgen [1.6K]
4 years ago
5

Theta = 11pi /6 in standard position

Mathematics
1 answer:
xxMikexx [17]4 years ago
4 0
Standard position would be 2pi-11pi/6, or pi/6 in the fourth quadrant
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Answer this question showing work. 2b − 7 ≥− 14 + 2b
jeka94

Answer:

No solution

Step-by-step explanation:

This answer has no solution, follow these steps to see how.

First, you add 7 on both sides.

Then you should have 2b > -7 +2b

You see how there is a 2b on both sides? this makes the problem unsolvable.

Say you were to continue though. You would subtract 2b on both sides and end up getting 0 > -7.  Therefore there is no solution.

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x=2/11 hope is right

Step-by-step explanation:

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\huge\text{Hey there!}

\rm{-2x + 4 > 8}

\large\textsf{SUBTRACT  4 to BOTH SIDES}

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\large\textsf{CANCEL puts 4 - 4 because that gives you 0}

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\mathsf{\dfrac{-2}{-2}>\dfrac{4}{-2}}

\mathsf{CANCEL\  out: \dfrac{-2}{-2}\  because\  that\  gives\  you\  1}

\mathsf{KEEP: \dfrac{4}{-2} \ because \ it \ helps \you \ compare\  to \  the \ x-value }

\mathsf{\dfrac{4}{-2} = \boxed{\bf -2}}

\rm{\bold{x < -2 }}

\rm{It\ is \ an\  O PENED \ circle \  shaded \  to \ the \ left \ side \ of \ the \ number  \ line}

\boxed{\boxed{\large\textsf{Answer: } \mathsf{\bf x < -2}}}\huge\checkmark

\large\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

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What is the answer to 7,8 I know I circle something but I guessed
guapka [62]
1 is a thanks for letting me help
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