I hope the choices for the numerators of the solutions are given.
I am showing the complete work to find the solutions of this equation , it will help you to find an answer of your question based on this solution.
The standard form of a quadratic equation is :
ax² + bx + c = 0
And the quadratic formula is:
x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}
So, first step is to compare the given equation with the above equation to get the value of a, b and c.
So, a = 10, b = -19 and c = 6.
Next step is to plug in these values in the above formula. Therefore,
So,
So,
Hope this helps you!
The answer is B. Carlos worked two hours and earned $20
Answer:
11.) 10w^2 + 43w + 21.
12.) -15y^2 - 2y + 8
Check the explanation for details
Step-by-step explanation:
11.) You are meant to multiply each row by both columns. For instance, multiply 5w by 2w and 7 you will get 10 w^2 and 35 w
Also, multiply 3 by both 2w and 7 you will get 6w and 21. Therefore,
Expansion of ( 5w + 3 )( 2w + 7 ) will produce 10w^2 + 37w + 6w + 21
= 10w^2 + 43w + 21.
12.) Repeat the same process by multiplying row by column.
Multiply -3y by 5y and 4 you will get -15y^2 and -12y.
Also, multiply 2 by same 5y and 4. You will get 10y and 8
Therefore, the expansion of
( -3y + 2 )( 5y + 4 ) will be
-15y^2 - 12y + 10y + 8
-15y^2 - 2y + 8
P = 11 + 4 + 18 + 37 + 7 + 19 = 96
a = (18*7) + (11*19) = 126 + 209 = 335
Answer:
C
Step-by-step explanation:
