Radius of curvature = 10'
Diameter of circle = 2 * 10' = 20'
height of segment = 2'
Let semi-chord be x.
Then by the intersecting chord property,
2*(20-2)=x^2
x^2=36
x=sqrt(36)=6
=>
chord=2x=2*6=12'
State the domain of the relation R{(-3,3), (1,1), (0,2),(1,-4),(5,-1)} and then State the range of the relation R={(-3,3), (1,1)
harina [27]
The range is the Y value and the Domain is the X value.
2 (an - 1) = 40
2an - 2 =40
2an = 40 - 2
2an = 38
2an/2 = 38/2
an = 19
70? Is this a trick question?
The answer is B because a linear function is y=mx+b
