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arlik [135]
3 years ago
5

Pia printed 2 maps of a walking trail. The length of the trail on the first map is 8 cm. The length of the trail on the second m

ap is 6 cm.
I already know A, please answer B for me.

A landmark on the first map is a triangle with side lengths of 3mm, 4mm, and 5mm. What is the scale factor from the first map to the second map. What are the side lengths of the landmark on the second map.

SHOW ALL YOUR WORK!!!
Mathematics
1 answer:
Marianna [84]3 years ago
5 0
The scale factor from the first map to the second map can be determined by:

scale factor = (length of trail in first map) / (length of trail in second map)

8 cm / 6 cm = 1.33

The landmark on the first map is a triangle with side lengths of 3mm, 4mm, and 5mm. 

3mm = 3 * 1.33 mm = 3.99mm
4mm = 4 * 1.33 mm = 5.32mm
5mm = 5 * 1.33 mm = 6.65mm

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Answer:

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It takes a train 60 seconds to completely drive through a bridge of 1260 m, and 90 seconds to completely drive through a tunnel
Olegator [25]

The length of train is 120 meters

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<u><em>Solution:</em></u>

The speed is given by formula:

speed = \frac{distance}{time}

Given that,

It takes a train 60 seconds to completely drive through a bridge of 1260 m

And 90 seconds to completely drive through a tunnel of 2010 m

Let the length of the train be "x"

<em><u>The total distance travelled by the train across the bridge is given by:</u></em>

total distance = x + 1260 + x = 2x + 1260

[ here we use x + x to represent that train completely drives through bridge ]

The time taken is given as 60 seconds

<em><u>Therefore, the speed is given as:</u></em>

speed = \frac{2x+ 1260}{60}

<em><u>The total distance travelled by the train through the tunnel is given by:</u></em>

total distance = x + 2010 + x = 2x + 2010

The time taken is given as 90 seconds

<em><u>Therefore, the speed is given as:</u></em>

speed = \frac{2x+ 2010}{90}

The speed of the train was the same in both cases.

Equate both speeds

\frac{2x+ 1260}{60} = \frac{2x+ 2010}{90}

\frac{x+630}{30} = \frac{x+1005}{45}

45(x+630) = 30(x+1005)\\\\45x + 28350 = 30x + 30150\\\\45x - 30x = 30150 - 28350\\\\15x = 1800\\\\x = 120

Thus length of train is 120 meters

<em><u>Find the speed of train:</u></em>

speed = \frac{2x+ 1260}{60}\\\\speed = \frac{2(120) + 1260)}{60}\\\\speed = 25

Thus speed of train is 25 meter per second

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