280 because if you divide 175 by 5 you get 35 which is the amount of miles the van travels in 1 hour and then you multiple 35 by 8 and you have your answer 280
The correlation coefficient is -0.87; strong correlation
<h3>How to determine the correlation coefficient?</h3>
The given parameters are:
x = Time spent working out
y = lbs Overweight
Next, we enter the table of values in a graphing tool.
From the graphing tool, we have the following summary:
<u>X Values</u>
- ∑ = 27.1
- Mean = 2.71
- ∑(X - Mx)2 = SSx = 22.569
<u>Y Values</u>
- ∑ = 89
- Mean = 8.9
- ∑(Y - My)2 = SSy = 778.9
<u>X and Y Combined</u>
- N = 10
- ∑(X - Mx)(Y - My) = -114.19
<u>R Calculation</u>
r = ∑((X - My)(Y - Mx)) / √((SSx)(SSy))
r = -114.19 / √((22.569)(778.9))
r = -0.8613
Approximate
r = -0.87
This means that the correlation coefficient is -0.87
Also, the correlation coefficient is a strong correlation, because it is closer to -1 than it is to 0
Read more about correlation coefficient at:
brainly.com/question/27226153
#SPJ1
Answer:
8 weeks
Step-by-step explanation:
So first you find out how much money he makes per week, by doing 7.5 x 20 you will find that. Now you need to find how many weeks it will take, find this by dividing 1200 by the amount he makes per week and you will end up with 8.
Answer:
I’m pretty sure it’s 73% but I’m not completely sure
Let's call the stamps A, B, and C. They can each be used only once. I assume all 3 must be used in each possible arrangement.
There are two ways to solve this. We can list each possible arrangement of stamps, or we can plug in the numbers to a formula.
Let's find all possible arrangements first. We can easily start spouting out possible arrangements of the 3 stamps, but to make sure we find them all, let's go in alphabetical order. First, let's look at the arrangements that start with A:
ABC
ACB
There are no other ways to arrange 3 stamps with the first stamp being A. Let's look at the ways to arrange them starting with B:
BAC
BCA
Try finding the arrangements that start with C:
C_ _
C_ _
Or we can try a little formula; y×(y-1)×(y-2)×(y-3)...until the (y-x) = 1 where y=the number of items.
In this case there are 3 stamps, so y=3, and the formula looks like this: 3×(3-1)×(3-2).
Confused? Let me explain why it works.
There are 3 possibilities for the first stamp: A, B, or C.
There are 2 possibilities for the second space: The two stamps that are not in the first space.
There is 1 possibility for the third space: the stamp not used in the first or second space.
So the number of possibilities, in this case, is 3×2×1.
We can see that the number of ways that 3 stamps can be attached is the same regardless of method used.
