All categories

4 years ago

10. Use the properties of exponents to simplify the expression:

Mathematics

1 answer:

aivan3 [116]4 years ago

7 0

<h3><u>Answer</u> :</h3>

$\bigstar\:\boxed{\bf{\purple{x^{\frac{m}{n}}}=\orange{(\sqrt[n]{x})^m}}}$

Let's solve !

$:\implies\sf\:25^{\frac{3}{2}}$

$:\implies\sf\:(\sqrt[2]{25})^3$

$:\implies\sf\:5^3$

$:\implies\boxed{\bf{\red{125}}}$

<u>Hence, Oprion-D is correct</u> !

You might be interested in

Find the area of a circle with radius 6yd.

velikii [3]

Answer:

X30

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

50 POINTS PLEASE SOLVE CORRECTLY!! How do you solve these 2 problems?

Andrew [12]

Ok, so abc is a 3 digit number

easy

if we do
abc=x
then we have
750-x=x
add x to both sides
750=2x
divide both sides by 2
375=x
abc=375

check
750-375=375

correct

abc=375
0.abc=0.375

0.abc=0.375
that was fun

7 0

3 years ago

A population has the following characteristics.(a) A total of 25% of the population survives the first year. Of that 25%, 75% su

zaharov [31]

Answer:

After 1st year, the age distribution will be

$x_1 = \left[\begin{array}{ccc}1584\\36\\108\end{array}\right]$

After 2nd year, the age distribution will be

$x_2 = \left[\begin{array}{ccc}5256\\396\\27\end{array}\right]$

Step-by-step explanation:

A population has the following characteristics.

A total of 25% of the population survives the first year. Of that 25%, 75% survives the second year.

The average number of offspring for each member of the population is 3 the first year, 5 the second year, and 3 the third year.

From the above information, we can construct a transition age matrix.

$A = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right]$

The population now consists of 144 members in each of the three age classes.

From the above information, we can construct the current age matrix.

$x = \left[\begin{array}{ccc}144\\144\\144\end{array}\right]$

How many members will there be in each age class in 1 year?

After 1st year, the age distribution will be

$x_1 = A \cdot x$

$x_1 = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right] \times \left[\begin{array}{ccc}144\\144\\144\end{array}\right]$

The matrix multiplication is possible since the number of columns of first matrix is equal to the number of rows of second matrix.

$x_1 = \left[\begin{array}{ccc}1584\\36\\108\end{array}\right]$

After 2nd year, the age distribution will be

$x_2 = A \cdot x_1$

$x_2 = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right] \times \left[\begin{array}{ccc}1584\\36\\108\end{array}\right]$

$x_2 = \left[\begin{array}{ccc}5256\\396\\27\end{array}\right]$

4 0

4 years ago

In a circle with radius 5 cm, how long can the longest chord be?

Ierofanga [76]

Answer:

photomath is the best app you can find

6 0

4 years ago

Target offered a 40% discount off the original

Setler [38]

Answer:

jdbfdbgfdugdvudh

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers