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Nikolay [14]
3 years ago
13

A population has the following characteristics.(a) A total of 25% of the population survives the first year. Of that 25%, 75% su

rvives the second year. The maximum life span is 3 years.(b) The average number of offspring for each member of the population is 3 the first year, 5 the second year, and 3 the third year.The population now consists of 144 members in each of the three age classes. How many members will there be in each age class in 1 year?0 ≤ age ≤ 1 = 1 ≤ age ≤ 2 = 2 ≤ age ≤ 3 = In 2 years?0 ≤ age ≤ 1 = 1 ≤ age ≤ 2 = 2 ≤ age ≤ 3 =
Mathematics
1 answer:
zaharov [31]3 years ago
4 0

Answer:

After 1st year, the age distribution will be

x_1 = \left[\begin{array}{ccc}1584\\36\\108\end{array}\right]

After 2nd year, the age distribution will be

x_2 = \left[\begin{array}{ccc}5256\\396\\27\end{array}\right]

Step-by-step explanation:

A population has the following characteristics.

A total of 25% of the population survives the first year. Of that 25%, 75% survives the second year.

The average number of offspring for each member of the population is 3 the first year, 5 the second year, and 3 the third year.

From the above information, we can construct a transition age matrix.

A = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right]

The population now consists of 144 members in each of the three age classes.

From the above information, we can construct the current age matrix.

x = \left[\begin{array}{ccc}144\\144\\144\end{array}\right]

How many members will there be in each age class in 1 year?

After 1st year, the age distribution will be

x_1 = A \cdot x

x_1 = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right] \times \left[\begin{array}{ccc}144\\144\\144\end{array}\right]

The matrix multiplication is possible since the number of columns of first matrix is equal to the number of rows of second matrix.

x_1 = \left[\begin{array}{ccc}1584\\36\\108\end{array}\right]

After 2nd year, the age distribution will be

x_2 = A \cdot x_1

x_2 = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right] \times \left[\begin{array}{ccc}1584\\36\\108\end{array}\right]

x_2 = \left[\begin{array}{ccc}5256\\396\\27\end{array}\right]

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