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bonufazy [111]
3 years ago
9

How many yards are in 5 miles?

Mathematics
1 answer:
Margaret [11]3 years ago
3 0
1 yard = 1760 yard x 5 = 8,800 which is b
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Please help with this question
svetlana [45]

Answer:

Segment JK is a chord in circle H

Line LM is a secant to circle H

Step-by-step explanation:

* Lets revise some definition in the circle

- The radius of the circle is a line segment drawn from the center of  

 the circle to a point on the circumference of the circle

- The chord of a circle is a line segment whose endpoints lie on the

 circumference of the circle

- The secant is a line intersect the circle in two points

- The tangent is a line touch or intersect the circle in one point

* Now lets solve the problem

- In circle H

∵ JK is a segment in circle H

∵ Point J lies on the circumference of circle H

∵ Point K lies on the circumference of circle H

∴ Segment JK is a chord in circle H

∵ LM is a line

∵ LM intersect circle H in two points L and M

∴ Line LM is a secant to circle H

4 0
3 years ago
Factor this trinomial 4x^2-6x-10 If you can please try to show me how to do it.
lilavasa [31]

Answer:

=2(2x-5)(x+1)

Step-by-step explanation:

So we have the trinomial:

4x^2-6x-10

First, factor out a 2:

=2(2x^2-3x-5)

Now, factor within the parentheses.

To do so, we want to find two numbers. When multiplied, these two numbers must equal (a)(c) and when added, they must equal b

(a)(c) is 2(-5) or -10 and b is -3. So, we want two numbers that when multiplied together gives -10 and when added gives -3.

-5 and 2 works. Therefore:

=2(2x^2-3x-5)

Replace -3x with 2x and -5x:

=2(2x^2+2x-5x-5)

Factor out a 2x for the first two terms. And factor out a negative 5 for the remaining two:

=2(2x(x+1)-5(x+1))

Grouping:

=2(2x-5)(x+1)

And we're done!

8 0
3 years ago
Evaluate (a + b)2 for a = 2 and b = 3.<br> 10<br> 25<br> 13
fgiga [73]

Answer:

10

Step-by-step explanation:

( 2 + 3 ) × 2

5 × 2 = 10

5 0
4 years ago
Read 2 more answers
A campground consists of 8 square campsites arranged in a line along a beach. The distance from the edge of a campsite to the wa
Sedaia [141]
The width of one campsite is 30.5 yards.

The campsite area has a 1220 square yards and a width of 5 yards.
If we divide 1220 by 5, we see that the total length of the campgrounds must be 244 yards.

Now, divide 244 by 8 and you will get that each campground is 30.5 yards wide.

(Unless, you forgot to include the distance of the campground with the given width, that would change our answer)
8 0
3 years ago
A square has a side length of 10cm. Work out the length of a diagonal of the square.​
Vitek1552 [10]

Answer: Let x = the length of a side of the square

a2 + b2 = c2

x2 + x2 = 102

2x2 = 100

x2 = 50

x = √50

x = 5√2 cm

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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