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Whitepunk [10]
3 years ago
11

Please help me on number 2!!

Mathematics
1 answer:
Gre4nikov [31]3 years ago
6 0
The question is already solved, but I am adding a response so it won't show up on the unanswered list.
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A NASA spacecraft measures the rate R of at which atmospheric pressure on Mars decreases with altitude. The result at a certain
AysviL [449]

Answer:

R = 0.0000498 \frac{KJ}{ m m^3}=0.0000498 \frac{KJ}{m^4}=4.98x10^{-5}\frac{KJ}{m^4}

Step-by-step explanation:

For this case we have the following value:

R = 0.0498 \frac{Kpa}{Km}

We can convert this first to \frac{Kpa}{m} like this:

R=0.0498 \frac{Kpa}{Km} *\frac{1km}{1000m}=0.0000498 \frac{Kpa}{m}

Now we use the fact the the pressure is defined as P =\frac{F}{A}, whre P is the pressure, F the force and A the area, so then Kpa= \frac{KN}{m^2} and then we can replace this:

R=0.0000498 \frac{KN}{m^3}

Now from definition of work we know that W= Fd where W is the work, F the force and d the distance, so then is equivalent KN =\frac{KJ}{m}

And if we replace this into the equation we got:

R = 0.0000498 \frac{KJ}{ m m^3}=0.0000498 \frac{KJ}{m^4}=4.98x10^{-5}\frac{KJ}{m^4}

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