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2 years ago

Please help me on number 2!!

Mathematics

1 answer:

Gre4nikov [31]2 years ago

6 0

The question is already solved, but I am adding a response so it won't show up on the unanswered list.

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(36 - 4)(6+2)<br> Standard form

jolli1 [7]

The answer is 256 ,

explanation- 6+2 is 8 and 36-4 is 32. 8 times 32= 256

3 0

3 years ago

1.) You are the crew chief of the Algebra 2 formula racing team. Your current task is to

s344n2d4d5 [400]

Answer:

a). Mileage for carA= $\frac{2}{x}$ , and mileage for carB= $\frac{ 3x+2}{x(x+1)}$

b).total mileage for both is similar to average of them= $\frac{(mileageA + mileageB)}{2}$

= $\frac{5x+4}{2x(x+1)}[tex]mil/gal$

Step-by-step explanation:

It is given that the distance traveled by car $A=2x+2=2(x+1)$

And distance traveled by car $B= 3x+2$

We know the mileage is mile/gallon,

a).So mileage of car $A= \frac{distance traveled by car A}{gallos of fuel used}$

$=\frac{2x+2}{x^2 +x}\\ =\frac{2(x+1)}{x(x+1)} \\=\frac{2}{x}mil/gal$

Similarly , the mileage for car $B= \frac{distance traveled by car A}{gallons of fuel used}$

$=\frac{3x+2}{x^2+x} \\=\frac{3x+2}{x(x+1)}$ $mil/gal$

b).total mileage for both is similar to average of them= $\frac{(mileageA + mileageB)}{2}$

$=\frac{2x+2}{x(x+1)}+\frac{3x+2}{x(x+1)}\\ =\frac{2x+2+3x+2}{x(x+1)}\\=\frac{5x+4}{x(x+1)}mil/gal$

Now divide by 2 for total(average) mileage.

$\frac{\frac{5x+4}{x(x+1)} }{2}\\ =\frac{5x+4}{2x(x+1)} mil/gal$ .

Thus those are the answers.

4 0

3 years ago

Help with these math exercises, please!

lions [1.4K]

1) (3-x) x (3+x)

2) 5(5-x) x (5+x)

3) (3v-wy) x (3v+wy)

4) 2(k-m) x (k+m) x (k^2+m^2)

5) (ab-4c) x (ab+4c)

Brainliest?

4 0

2 years ago

Internet providers: In a survey of 935 homeowners with high-speed Internet, the average monthly cost of a high-speed Internet pl

BlackZzzverrR [31]

Answer:

68% of plans cost between $62.16 and $86.52.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean: 74.34

Standard deviation: 12.18

Bell-shaped is the same as normally distributed.

Estimate the number of plans that cost between $62.16 and $86.52.

62.16 is one standard deviation below the mean.

86.52 is one standard deviation above the mean.

By the Empirical rule, 68% of the measures are within 1 standard deviation of the mean.

68% of plans cost between $62.16 and $86.52.

7 0

2 years ago

In the survey 12 students said that they would like to learn French Spanish was 36% French 24% German 18% other 22% how many stu

Rufina [12.5K]

200 hundred students were surveyed DUH!

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2 years ago