3 years ago

For a regular 15-gon:

Mathematics

1 answer:

kompoz [17]3 years ago

3 0

A)2340
b)156
c)360
d)24
e)180, they are supplementary angles

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Please help me, im struggling

Molodets [167]

Part 1

$f(a)=4-7a+16a^2$

Part 2

$f(a+h)=4-7(a+h)+16(a+h)^2\\\\=4-7(a+h)+16(a^2 +2ah+h^2)\\\\=4-7a-7h+16a^2 +32ah+16h^2$

Part 3

$\frac{f(a+h)-f(a)}{h}=\frac{(4-7a-7h+16a^2 +32ah+16h^2-(4-7a+16a^2)}{h}\\\\=\frac{-7h+32ah+16h^2}{h}\\\\=32a+16h-7$

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1 year ago

Central High wants to estimate the number of seniors who plan to go to a 4-year college. Answer the following.

Elodia [21]

Answer:

390 seniors

Step-by-step explanation:

13/20=.65

600x .65=390

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2 years ago

Read 2 more answers

There are two coins in a bag. for coin 1, p(h) = ½ and for coin 2, p(h) = 1/3. your friend chooses one of the coins at random an

lana [24]

The answer is 3 to this question

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3 years ago

Help needed!

Jet001 [13]

Answer:

15 inches

Step-by-step explanation:

The ratio of sides in 30º-60º-90º triangle is:

a : b : c = 1 : √3 : 2

If a is 5√3, the length of b is:

b = a√3 = 5√3 *√3 = 5*3 = 15

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2 years ago

Find the perimeter of a triangle with vertices A(2,5) B(2,-2) C(5,-2). Round your answer to the nearest tenth and show your work

valina [46]

Answer:

Step-by-step explanation:

Question

Find the perimeter of a triangle with vertices A(2,5) B(2,-2) C(5,-2). Round your answer to the nearest tenth and show your work.

perimeter of a triangle = AB+AC+BC

Using the distance formula

AB = sqrt(-2-5)²+(2-2)²

AB = sqrt(-7)²

AB =sqrt(49)

AB =7

BC = sqrt(-2+2)²+(2-5)²

BC = sqrt(0+3²)

BC =sqrt(9)

BC =3

AC= sqrt(-2-5)²+(2-5)²

AC= sqrt(-7)²+3²

AC =sqrt(49+9)

AC =sqrt58

Perimeter = 10+sqrt58

5 0

2 years ago