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4vir4ik [10]
3 years ago
10

Find the derivative of the function y=x^3-8x^2+21x+1

Mathematics
1 answer:
aleksandrvk [35]3 years ago
6 0
y=x^3-8x^2+21x+1 \\
y'=3x^2-16x+21
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5x=4y+8 3y=3x-3 using elimination
suter [353]
Let's rewrite the equation with x and y on the left side of the equal sign.  
5x-4y=8 --------(1) 
3x-3y=3---------(2)  
Divide equation (2) by 3, 
x - y= 1 
now we have, 
5x-4y = 8 --------(1) 
x - y = 1 ---------(2)  
To eliminate x, multiply equation (2) by 5. This makes both the coefficients of x to be 5. Subtract the second equation from the first equation.  
5x - 4y = 8 
(2) * 5 5x - 5y = 5 
(-) (+) (-) 
---------------- 
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 Therefore, y=3 
 Substitute the value of y, in any one of the two equations. Let's substitute y in the second equation.
 x-3=1
 x=4 
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