Thus L.H.S = R.H.S that is 2/√3cosx + sinx = sec(Π/6-x) is proved
We have to prove that
2/√3cosx + sinx = sec(Π/6-x)
To prove this we will solve the right-hand side of the equation which is
R.H.S = sec(Π/6-x)
= 1/cos(Π/6-x)
[As secƟ = 1/cosƟ)
= 1/[cos Π/6cosx + sin Π/6sinx]
[As cos (X-Y) = cosXcosY + sinXsinY , which is a trigonometry identity where X = Π/6 and Y = x]
= 1/[√3/2cosx + 1/2sinx]
= 1/(√3cosx + sinx]/2
= 2/√3cosx + sinx
R.H.S = L.H.S
Hence 2/√3cosx + sinx = sec(Π/6-x) is proved
Learn more about trigonometry here : brainly.com/question/7331447
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Answer:
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Answer:
ao = 6 miles
a1 = 4 inches
a2 = 50 miles
Step-by-step explanation:
Scale Distance on map Distance in miles
1) 1/4 inch 1 mile
2.5 inches 10 miles
2) 1/2 inch 1 mile
3.0 inches <u> _6____miles </u>
3) 1 inch 1 mile
3.0 inches 3 miles
4) 1 inch 5 miles
<u> </u><u> _4____ inche</u>s 20 miles
5) 1 inch 15 miles
2.0 inches 30 miles
6) 1 inch 25 miles
2.0 inches <u>_50__</u>_____ miles
Thank you.
