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snow_tiger [21]
4 years ago
6

PLEASE HELP I WILL GIVE YOU 15 POINTS. WARNING 8TH GRADE MATH!

Mathematics
1 answer:
Digiron [165]4 years ago
5 0
You need to show us the graph
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Solving systems by Substitution Homework y=x+4 y=x-3​
zvonat [6]
There is no solution for this equation since they have the same slope, x/1. The only difference between these two is that their y intercepts are different meaning that they will be parallel lines that will never intersect among one other. For example, think of it as two separate lines that are have the same slope and never gain more distance/units from one another.


Solve:

To solve, you have to get one of this equations into a Ax+By=C equation form, standard equation. Let’s change y=x+4 into a standard equation.

We have to get x and y together and 4 as C.
So let’s subtract x from both sides;

y=x+4
-x -x
————————
-x+y=4

This is a standard equation.

Now let’s substitute.

take the standard equation and plug in y which is x+4 since there is a equation meaning it’s y=x+4


-x+(x+4)=4


Let’s simplify this mess.


-x+x equals 0. So we are left with 4=4.

Subtract 4 from both sides and we get 0=0



This means there is no solution. Hoped this helped.
8 0
3 years ago
Write an equation of the parabola that has the same shape as the graph of f(x)=3x^2, but with the point (7,-2) as the vertex
nordsb [41]

Hello!

\large\boxed{f(x) = 3(x - 7)^{2}  - 2}

Recall that the transformations form of a parabola is:

f(x) = ±a(b(x-h)) + k where:

a = vertical stretch/compression

b = horizontal stretch/compression

h = horizontal shift, x-coordinate of vertex

k = vertical shift, y-coordinate of vertex

In this instance, the parent function is f(x) = 3x^2. There is a vertical stretch of 3.

However, there is a point (7, -2) that needs to be included. Substitute these values into the transformation formula:

h = 7

k = -2

f(x) = 3(x - 7)² - 2 is the equation with (7, -2) as the vertex.

4 0
4 years ago
Gold fish or cheez its​
babymother [125]

Answer: gold fish

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
Write the equation of the line that passes through the points (8, –1) and (2, –5) in standard form, given that the point-slope f
dolphi86 [110]

Answer:

A linear equation in the standard form is written as:

y = a*x +b

where a is the slope and b is the y-intercept.

If we know that the line passes through the points (a, b) and (c, d), then the slope can be written as:

a = (d - b)/(c - a)

So we know that our line passes through the points (8, -1) and (2, -5)

then the slope will be:

a = (-5 - (-1) )/(2 - 8) = (-4/-6)  = 2/3

Then our line is something like:

y = (2/3)*x + b

to find the value of b, we can use the fact that we know that our line passes through the point (2, -5)

this means that when x = 2, we must have y = -5

replacing these values in the equation we get:

-5 = (2/3)*2 + b

-5 = 4/3 + b

-5 - 4/3 = b

-15/3 - 4/3 = b

-19/3 = b

then the equation is:

y = (2/3)*x - 19/3

(in the question you wrote the point-slope form, but you can see that it does not work for the second point, so there may be a mistake there, as the slope is missing)

The actual equation in the point-slope form is:

y + 1 = (2/3)*(x - 8)

4 0
3 years ago
The perimeter of a square is 2 meters. How many centimeters long is each side?​
Rzqust [24]

Answer:

0.5 meters (50 cm.)

Explanation: 2 divided by 4=0.5=50 cm.

8 0
3 years ago
Read 2 more answers
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