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Veseljchak [2.6K]
3 years ago
10

Solving systems by Substitution Homework y=x+4 y=x-3​

Mathematics
1 answer:
zvonat [6]3 years ago
8 0
There is no solution for this equation since they have the same slope, x/1. The only difference between these two is that their y intercepts are different meaning that they will be parallel lines that will never intersect among one other. For example, think of it as two separate lines that are have the same slope and never gain more distance/units from one another.


Solve:

To solve, you have to get one of this equations into a Ax+By=C equation form, standard equation. Let’s change y=x+4 into a standard equation.

We have to get x and y together and 4 as C.
So let’s subtract x from both sides;

y=x+4
-x -x
————————
-x+y=4

This is a standard equation.

Now let’s substitute.

take the standard equation and plug in y which is x+4 since there is a equation meaning it’s y=x+4


-x+(x+4)=4


Let’s simplify this mess.


-x+x equals 0. So we are left with 4=4.

Subtract 4 from both sides and we get 0=0



This means there is no solution. Hoped this helped.
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What is the perimeter of a square with sides that measure 2x + 3 units?
PtichkaEL [24]

Answer:

8x+12

Step-by-step explanation:

We know that squares have equal sides. To calculate perimeter, just add up all of the 4 sides.

2x+3+2x+3+2x=3+2x+3

Add like terms:

8x+12

You could also multiply by four:

4(2x+3)

Use distributive property:

8x+12

8 0
3 years ago
Need help! Does anyone know how to do this type of math? (It's geometry)
mart [117]

Answer:

71

Step-by-step explanation:

<u>refer</u><u> </u><u>the</u><u> attachment</u>

to solve the question we need to recall one of the most important theorem of circle known as two tangent theorem which states that <u>tangents </u><u>which</u><u> </u><u>meet </u><u>at</u><u> the</u><u> </u><u>same</u><u> </u><u>point</u><u> </u><u>are </u><u>equal</u><u> </u><u> </u>that is being said

  • FA=AI=17
  • CH=CG=2.5

since \rm BA=FA+FB and it's given that FA and BA are 17 and 29 FB should be

  • \rm 29=17+FB

therefore,

  • FB=29-17=\boxed{12}

once again by two tangent theorem we acquire:

  • FB=BH=\boxed{12}

As BC=BH+CH,BC is

  • 12+2.5
  • \boxed{14.5}

likewise,AD=AI+DI so,

  • 21=17+DI [AD=21(given) and AI=17 (by the theorem)]

thus,

  • DI=21-17=\boxed{4}

By the theorem we obtain:

  • DI=DG=4

Similarly,DC=DG+CH therefore,

  • DC=4+2.5=\boxed{6.5}

Now <u>finding</u><u> </u><u>the</u><u> </u><u>Perimeter</u><u> </u><u>of </u><u>ABCD</u>

  • P_{\text{ABCD}}=\text{AB+AD+BC+DC}

substitute what we have and got

  • P_{\text{ABCD}}=\text{29+21+14.5+6.5}

simplify addition:

  • P_{\text{ABCD}}=\boxed{71}

hence,

the Perimeter of ABCD is <u>7</u><u>1</u>

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2 years ago
HELP MEE!!!
SIZIF [17.4K]

A- none because they are parallel lines

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Answer:

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Step-by-step explanation:

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angle formed by two chords in a circle

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