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Bess [88]
4 years ago
15

I need help with questions number seven and ten. Answering will give you 28 pts

Mathematics
1 answer:
Anika [276]4 years ago
3 0

Answer:

#7=A

#10=

Step-by-step explanation:

for #10 idk the answer but its kind of similar to number 7

sorry


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The area of a rectangular wall of a barn is 192 sq. Ft. It's length is 8 ft. Longer than twice it's width. Find the length and w
Novay_Z [31]

Answer: length = 24 ft

Width = 8 ft

Step-by-step explanation:

Let L represent the length of the barn.

Let W represent the width of the barn.

The area of a rectangular wall of a barn is 192 sq. Ft. This means that

LW = 192- - - - - - - - - - - - - - -1

It's length is 8 ft longer than twice it's width. This means that

L = 2W + 8

Substituting L = 2W + 8 into equation 1, it becomes

W(2W + 8) = 192

2W² + 8W = 192

2W² + 8W - 192 = 0

Dividing through by 2, it becomes

W² + 4W - 96 = 0

W² + 12W - 8W - 96 = 0

W(W + 12) - 8(W + 12) = 0

(W - 8)(W + 12) = 0

W = 8 or W = - 12

Since the width cannot be negative, then W = 8

L = 192/W = 192/8

L = 24

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3 years ago
The area of this rectangle is 96 ft2.<br> What is the length and width?
chubhunter [2.5K]

Answer:

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Step-by-step explanation:

the equation to solve this would be

x*(x+4)=96

you isolate the variable by dividing each side by factors that doesn't contain the variable

X would then equal 8

length is 8

width is 8+4= 12

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Answer:

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Step-by-step explanation:

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