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joja [24]
3 years ago
15

Add these measurements, using significant digit rules: 1.0090 cm + 0.02 cm = cm

Physics
1 answer:
Luda [366]3 years ago
8 0

Answer:  " 1.03 " .

____________________________________

Explanation:

_____________________________________

When we add "measured" or "obtained values" ; the rules for "signficant digits" (also known as "significant figures" ; or "sig figs")  are different from the rules we use when we multiply "measured or obtained values".

We are given 2 (two) "measured or obtained values" ; and we are asked to add these values together using the "significant digit rules.

In this case, we add up the "sum total value" of all the values—Not taking into account the number of significant figures.  Then, we take that "sum value" ; and we round that value to the number of "decimal places" that corresponds to the the number of decimals places in the "measured/obtained valued" that occurs in the value using to calculate the sum —the one that also happens to have the least number of significant digits among all the values used to calculate the "sum total".

As such:

_____________________________________

              1.0090 cm

+            0.02      cm          

      ________________    

           1.0290  cm.                                    

                                   

 →  Now, there were two (2) values used to calculate the "sum total" ;

1)  1.0090 cm ; which has 5 (five) significant digits.

2)  0.02 cm ;  which as 1 (one)  significant digits.

_____________________________________

 So, " 1" is less than "5" ;  so:  " 0.02" is the value within the calculations used to find the sum total — that has the "least" number of significant digits.    

  →  " 0.02 " ;  happens to have 2 (two) decimal spaces.

_____________________________________

So, we take the "sum total" :

      →   "  1.0290 cm " ;

      →  And round this number to:  " 2 (two) decimal places:

            → 1.029... ;  

      →  If the number after the second decimal place is from "1 to 4" ; we round down.  If the number after the second decimal place is

from "5 and 9" ; to round up.  Since the third decimal place is:  "9" ;

  [Note:  " 1.02<u>9</u>.." ;  is between "5 to 9" } ; we round up:

→  The answer is:  " 1.03 " .

_____________________________________

Hope this is helpful to you!

     Wishing you the best!

_____________________________________

 

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Answer could be2 grains of rice
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Cells are visualized using light microscopes and electron microscopes. Which statement about microscopes is false. Group of answ
denpristay [2]

Answer:

Light microscopes use light and glass objectives to illuminate and magnify objects

Explanation:

Light microscopes and electron microscopes are used to study cells. The electron microscope has many times more resolving power than the ordinary light microscope. A light microscope contains an objective lens and an eyepiece through which the final image is seen.

Both light and electron microscopes magnifies the image of the object. The magnifying power of an electron microscope is many times that of the light microscope.

4 0
3 years ago
A ball of mass 0.250 kg and a velocity of + 5.00 m/s collides head-on with a ball of mass 0.800 kg that is initially at rest. No
Mademuasel [1]

Answer:

v_1=-2.616\ m/s

Explanation:

Given that,

Mass of ball 1, m_1=0.25\ kg

Initial speed of ball 1, u_1=5\ m/s

Mass of ball 2, m_2=0.8\ kg

Initial speed of ball 2, u_2=0 (at rest)

After the collision,

Final speed of ball 2, v_2=2.38\ m/s

Let v_2 is the final speed of ball 1.

Initial momentum of the system is :

p_i=m_1u_1+m_2u_2

p_i=0.25\times 5+0

p_i=1.25\ m/s

Final momentum of the system is :

p_f=m_1v_1+m_2v_2

p_f=0.25\times v_1+0.8\times 2.38

p_f=0.25 v_1+1.904

According the law of conservation of linear momentum :

initial momentum = final momentum

1.25=0.25 v_1+1.904

v_1=-2.616\ m/s

So, the final velocity of ball 1 is (-2.616)m/s.

8 0
3 years ago
A 5.2 cm diameter circular loop of wire is in a 1.35 T magnetic field. The loop is removed from the field in 0.29 sec. Assume th
Katyanochek1 [597]

Answer:

9.88 milivolt

Explanation:

Given: diameter d = 5.2 cm

magnetic field B_1 = 1.35 T, final magnetic field B_2 =0 T

t = 0.29 sec.

we know emf =  - dΦ/dt

and flux Φ = BA

A= area

therefore emf ε = -A(B_2-B_1)/Δt

=-\pi(d/2)^2\frac{B_2-B_1}{\Delta t} \\=-\pi(0.052/2)^2\frac{0-1.35}{0.29} \\=98.8\times10^4\\=9.88 mV

3 0
3 years ago
While driving north at 25 m/s during a rainstorm you notice that the rain makes an angle of 38 degrees with the vertical. while
ikadub [295]

While returning back in opposite direction driver see that rain drops are falling vertically down

so horizontal speed of rain with respect to driver must be Zero

while moving towards the north direction driver see that the rain drops makes an angle 38 degree with the vertical

tan\theta = \frac{v_y}{v_x}

tan38 = \frac{v_y}{25 + 25}

v_y = 39 m/s

so the speed of rain is

v = \sqrt{25^2 + 39^2}

v = 46.3 m/s

also the angle is given as

\theta = tan^{-1}\frac{39}{25}

\theta = 57.3 degree

8 0
4 years ago
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