The net force on the car for either case will be zero, since the car is moving at a constant velocity.
<h3>Net force on the car</h3>
The net force on the car is the sum of all the forces acting on the car.
∑F = ma
<h3>When the car is on a level road</h3>
When the car is on a level road, the only two forces acting on the car is the applied force and frictional force of the road.
F - Ff = 0
The net force will be zero, since the car is moving at a constant velocity.
<h3>When the car is on uphill</h3>
The forces acting on the car at the uphill is the applied force, weight of the car acting downwards and the frictional force acting opposite direction.
F - Wsinθ - μFₙcosθ = 0
The net force will be zero, since the car is moving at a constant velocity.
Learn more about net force at constant velocity here: brainly.com/question/14392124
Power is calculated as work per unit time, and work in turn is calculated as force multiplied by distance. In this case, the force required is equivalent to the weight of the barbell multiplied by acceleration due to gravity.
P = W/t = Fd/t = mgd/t = (200 kg)(9.81 m/s^2)(2 m)/2.2 s = 1783.64 Watts.
The answer is D. i got all the other ones wrong ._.
Answer:
False
Explanation:
The Concentration of Acid or Base is the ph of the solution.
Answer:
the yield of product is YP=46.835 % and the concentration of solids is
Cs = 27.33%
Explanation:
Assuming that all the solids and fats remains in the milk after the evaporation, then the mass of product mP will be
Mass of fat in 100 kg of milk = 100 kg* 0.037 = mP* 0.079
mP = 100 kg* 0.037/0.079 = 46.835 kg
then the yield YP of the product is
YP= mP / 100 kg = 46.835 kg / 100 kg = 46.835 %
YP= 46.835 %
the concentration of solids Cs is
Mass of solids in 100 kg of milk = 100 kg* 0.128 = 46.835 kg * Cs
Cs = 100 kg* 0.128 / 46.835 kg = 0.2733 = 27.33%
Cs = 27.33%