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Tatiana [17]
3 years ago
6

How to solve -8-7x+5=4

Mathematics
1 answer:
Vlad1618 [11]3 years ago
3 0
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation for example : -8-7x+-5(4)=0 . But the zero turned to -1 because a non zero constant never equals 0,but the problem doesn’t have a solution, but the answer is -1
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2/3 as a real number
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Answer:

Yes

Step-by-step explanation:

I don't know the question but 2/3 is a real number.

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3 years ago
[10] In the following given system, determine a matrix A and vector b so that the system can be represented as a matrix equation
irina1246 [14]

Answer:

y=-\frac{158}{579}

Step-by-step explanation:

To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:

A=\left[\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right]

And the vector B is formed with the solution of each equation of the system:b=\left[\begin{array}{c}3\\-3\\6\\1\end{array}\right]

To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called A_{2}.

A_{2}=\left[\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right]

The value of y using Cramer's rule is:

y=\frac{det(A_{2}) }{det(A)}

Find the value of the determinant of each matrix, and divide:

y==\frac{\left|\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right|}{\left|\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right|} =\frac{158}{-579}

y=-\frac{158}{579}

7 0
3 years ago
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Answer:

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Step-by-step explanation:

7 0
3 years ago
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Answer:

9

Step-by-step explanation:

Substitute 4 as k into the equation.

16 - 3(4) + 5

simplify

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4 + 5

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madam [21]
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