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3 years ago

6

How to solve -8-7x+5=4

1 answer:

Vlad1618 [11]3 years ago

3 0

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation for example : -8-7x+-5(4)=0 . But the zero turned to -1 because a non zero constant never equals 0,but the problem doesn’t have a solution, but the answer is -1

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What is the area of 18 1/3 if the height of the window is 3 1/3

marin [14]

You would find the answer by dividing 3 1/3 from 18 1/3.
55/3 / 10/3
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2 years ago

Question 8<br> Calculate the difference (4x2 + x - 5) – (5x2 - 1).

Rufina [12.5K]

Answer:

x - 6

Step-by-step explanation:

(4x2 + x - 5) - (5x2 - 1)

According to the order of operations, parenthesis come first so we will solve what is in the parenthesis first.

Then we do the multiplication because it comes before addition and subtraction.

4x2 = 8

Now we have 8 + x - 5

Combine like terms and 8-5=3 so we have 3 + x

Now for the second one.

5x2=10

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Subtracting this from the first expression we have:

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2 years ago

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Alex_Xolod [135]

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3 years ago

Solve the following triangle. Given A=51 degrees b=40 c=45

STALIN [3.7K]

Answer:

$a=36.87\ units$

$B=57.47^o$

$C=71.53^o$

Step-by-step explanation:

step 1

Find the length side a

Applying the law of cosines

$a^2=b^2+c^2-2(b)(c)cos(A)$

substitute the given values

$a^2=40^2+45^2-2(40)(45)cos(51^o)$

$a^2=1,359.4466$

$a=36.87\ units$

step 2

Find the measure of angle B

Applying the law of sines

$\frac{a}{sin(A)} =\frac{b}{sin(B)}$

substitute the given values

$\frac{36.87}{sin(51^o)} =\frac{40}{sin(B)}$

$sin(B)=\frac{sin(51^o)}{36.87}{40}$

$B=sin^{-1}(\frac{sin(51^o)}{36.87}{40})=57.47^o$

step 3

Find the measure of angle C

Remember that the sum of the interior angles in any triangle must be equal to 180 degrees

so

$A+B+C=180^o$

substitute the given values

$51^o+57.47^o+C=180^o$

$108.47^o+C=180^o$

$C=180^o-108.47^o=71.53^o$

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Step-by-step explanation:

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2 years ago

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