1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Yuki888 [10]
3 years ago
13

Shakeela is planning to buy a pair of pants that have an original price of $51. The pants are on sale for 50% off and the sales

tax is 5%.
Which estimate will give her a close approximation of the price she will have to pay?

A) $50 + $2.50

B) $30 + $1.50

C) $25 + $1.25

D) $45 + $2.50
Mathematics
1 answer:
Mila [183]3 years ago
6 0

Answer:

C) $25 + $1.25

Step-by-step explanation:

1.  51 x .5 = 25.5

2.  25.5 x .05 = 1.275

25 + 1.25  ≈  25.5 + 1.28

You might be interested in
Solve: 10(1 + 3y) = 20 <br> What does y equal?<br> Y =
marin [14]

Answer:

y = 1/3 ≈ 0.3

hope this helps! :)

6 0
3 years ago
A construction worker has a cable that is 8 yards long. He wants to cut it into 9 equal-length pieces. How long will each piece
Troyanec [42]
They would be 32 inches because I did it again and got 32 inches or 0.8 yards
long and if you need any more help or this wasn't correct just tell me :D

4 0
3 years ago
Read 2 more answers
Determine whether the given vectors are orthogonal, parallel or neither. (a) u=[-3,9,6], v=[4,-12,-8,], (b) u=[1,-1,2] v=[2,-1,1
nevsk [136]

Answer:

a) u v= (-3)*(4) + (9)*(-12)+ (6)*(-8)=-168

Since the dot product is not equal to zero then the two vectors are not orthogonal.

|u|= \sqrt{(-3)^2 +(9)^2 +(6)^2}=\sqrt{126}

|v| =\sqrt{(4)^2 +(-12)^2 +(-8)^2}=\sqrt{224}

cos \theta = \frac{uv}{|u| |v|}

\theta = cos^{-1} (\frac{uv}{|u| |v|})

If we replace we got:

\theta = cos^{-1} (\frac{-168}{\sqrt{126} \sqrt{224}})=cos^{-1} (-1) = \pi

Since the angle between the two vectors is 180 degrees we can conclude that are parallel

b) u v= (1)*(2) + (-1)*(-1)+ (2)*(1)=5

|u|= \sqrt{(1)^2 +(-1)^2 +(2)^2}=\sqrt{6}

|v| =\sqrt{(2)^2 +(-1)^2 +(1)^2}=\sqrt{6}

cos \theta = \frac{uv}{|u| |v|}

\theta = cos^{-1} (\frac{uv}{|u| |v|})

\theta = cos^{-1} (\frac{5}{\sqrt{6} \sqrt{6}})=cos^{-1} (\frac{5}{6}) = 33.557

Since the angle between the two vectors is not 0 or 180 degrees we can conclude that are either.

c) u v= (a)*(-b) + (b)*(a)+ (c)*(0)=-ab +ba +0 = -ab+ab =0

Since the dot product is equal to zero then the two vectors are orthogonal.

Step-by-step explanation:

For each case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

Part a

u=[-3,9,6], v=[4,-12,-8,]

The dot product on this case is:

u v= (-3)*(4) + (9)*(-12)+ (6)*(-8)=-168

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

|u|= \sqrt{(-3)^2 +(9)^2 +(6)^2}=\sqrt{126}

|v| =\sqrt{(4)^2 +(-12)^2 +(-8)^2}=\sqrt{224}

And finally we can calculate the angle between the vectors like this:

cos \theta = \frac{uv}{|u| |v|}

And the angle is given by:

\theta = cos^{-1} (\frac{uv}{|u| |v|})

If we replace we got:

\theta = cos^{-1} (\frac{-168}{\sqrt{126} \sqrt{224}})=cos^{-1} (-1) = \pi

Since the angle between the two vectors is 180 degrees we can conclude that are parallel

Part b

u=[1,-1,2] v=[2,-1,1]

The dot product on this case is:

u v= (1)*(2) + (-1)*(-1)+ (2)*(1)=5

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

|u|= \sqrt{(1)^2 +(-1)^2 +(2)^2}=\sqrt{6}

|v| =\sqrt{(2)^2 +(-1)^2 +(1)^2}=\sqrt{6}

And finally we can calculate the angle between the vectors like this:

cos \theta = \frac{uv}{|u| |v|}

And the angle is given by:

\theta = cos^{-1} (\frac{uv}{|u| |v|})

If we replace we got:

\theta = cos^{-1} (\frac{5}{\sqrt{6} \sqrt{6}})=cos^{-1} (\frac{5}{6}) = 33.557

Since the angle between the two vectors is not 0 or 180 degrees we can conclude that are either.

Part c

u=[a,b,c] v=[-b,a,0]

The dot product on this case is:

u v= (a)*(-b) + (b)*(a)+ (c)*(0)=-ab +ba +0 = -ab+ab =0

Since the dot product is equal to zero then the two vectors are orthogonal.

5 0
3 years ago
Read 2 more answers
If a bag contains 12 quarters, 6 dimes, and 18 nickles, what is the part-to-whole ratio of nickles to all coins?
zepelin [54]

Answer:

18/36 or 1/2

Step-by-step explanation:

There are 18 nickels, which is the numerator.

You add all the numbers together to get the denominator, which is 12+6+18=36.

Then, you put the two values in a fraction - 18/36

and simplify, to get you 1/2.

3 0
3 years ago
Write an algebraic expression using n the sum of a number and 7
liubo4ka [24]

Answer:

n+7

Step-by-step explanation:

When we have any unknown quantity, we can call it mostly x,y,z

so, here

Let take an unknown number = n

then

we need to do here " sum of a number and 7 in algebraic form"

so, it becomes

n + 7 (Answer)

6 0
3 years ago
Other questions:
  • Solve for x In the triangle
    10·1 answer
  • What is the value of x?<br><br><br><br> Enter your answer in the box.<br><br> x =
    10·2 answers
  • John's patio is 5 feet by 10 feet. He will be increasing the width and the length each by x feet. He wants the new area of his p
    9·1 answer
  • What is 98.044 rounded to the nearest hundred
    13·1 answer
  • Afire hydrant that is 2 3/4 feet tall casts a shadow that 2 feet long. Find the length of the shadow cast by a nearby 154-foot t
    6·1 answer
  • Kara buys 24 bagels. Ten are whole wheat. What fraction of the bagels are wheat? Write in simplest form.
    6·2 answers
  • A store pays $399 for a waterheater. The store marks up the price by 42% . What is the amount of the mark-up?
    14·1 answer
  • CAN SOMEONE PLZ HELP MEI BEG U ILL DO ANYTHING JUST HELP ME!!!!
    9·1 answer
  • A photograph with a width of 3 inches and a length of 5 inches will be enlarged so that the length is 40 inches. What will the w
    8·1 answer
  • In isosceles ∆ABC, points M and N belong to base
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!