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3 years ago

Please help please??i need this doneee please

Mathematics

2 answers:

goldfiish [28.3K]3 years ago

4 0

Answer:

18.84

Step-by-step explanation:

Arc length = r × theta

4 × 3pi/2

4 × 3 × 3.14/2

18.84

dolphi86 [110]3 years ago

3 0

Answer:

6pi

Step-by-step explanation:

First find the circumference of the entire circle

C = 2*pi*r

C = 2*pi*4

C = 8pi

We have 3/4 of the circle so multiply the circumference by the fraction of the circle

3/4*8pi

6pi

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RSB [31]

Answer:

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Step-by-step explanation:

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3 years ago

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What are the potential solutions of log4x+log4(x+6)=2?

lions [1.4K]

The potential solutions of $log_4x+log_4(x+6)=2$ are 2 and -8.

<h3>Properties of Logarithms</h3>

From the properties of logarithms, you can rewrite logarithmic expressions.

The main properties are:

Product Rule for Logarithms - $log_{b}(a*c)=log_{b}a+log_{b}c$
Quotient Rule for Logarithms - $log_{b}(\frac{a}{c} )=log_{b}a-log_{b}c$
Power Rule for Logarithms - $log_{b}(a^c)=c*log_{b}a$

The exercise asks the potential solutions for $log_4x+log_4(x+6)=2$ . In this expression you can apply the Product Rule for Logarithms.

$log_4x+log_4(x+6)=2\\ \\ x*(x+6)=4^2\\ \\ x^2+6x=16\\ \\ x^2+6x-16=0$

Now you should solve the quadratic equation.

Δ= $b^2-4ac=36-4*1*(-16)=36+64=100$ . Thus, x will be $x_{1,\:2}=\frac{-6\pm \:\sqrt{100} }{2\cdot \:1}=\frac{-6\pm \:10}{2}$ . Then:

$x_1=\frac{-6+10}{2}=\frac{4}{2} =2\\ \\ \:x_2=\frac{-6-10}{2}=\frac{-16}{2} =-8$

The potential solutions are 2 and -8.

Read more about the properties of logarithms here:

brainly.com/question/14868849

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2 years ago

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Answer: 16a + 8

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3 years ago

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777dan777 [17]

Answer:

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Step-by-step explanation:

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3 years ago