fog(x+2) = f(g(x+2) = f ( x+2+7)
= f(x+9)
= x+9- 4
(f g)(x + 2) = x+5
Answer:
good evening,
You should notice that :
n=4K or n=4K+1 or n=4K+2 or n=4K+3
If n=4k so n(n+1)(n+2)(n+3)is a multiple of 4
If n=4K+1 so n+3 =4(k+1) so n(n+1)(n+2)(n+3)is a multiple of 4
If n=4K+2 so n+2 =4(k+1) so n(n+1)(n+2)(n+3)is a multiple of 4
If n=4K+3 so n+1=4(k+1) so n(n+1)(n+2)(n+3)is a multiple of 4
:)
Answer:
A
Step-by-step explanation:
A function can't have the same number more than once, so the answer is A since there are no repeating numbers.