The PDF for the wait time (denoted by the random variable X) is
where λ = 1/75. We want to find Pr[X > 70 | X ≥ 40]. Pierre has already been waiting for 40 min, so if he waits another 30 min he will have waited for a total of 70 min.
By definition of conditional probability,
Pr[X > 70 | X ≥ 40] = Pr[X > 70 and X ≥ 40] / Pr[X ≥ 40]
If X > 70, then automatically X ≥ 40 is satisified, so the right side reduces to
Pr[X > 70 | X ≥ 40] = Pr[X > 70] / Pr[X ≥ 40]
Use the PDF or CDF to find the remaining probabilities. For instance, using the PDF,
Or, using the CDF,
Similarly, you'll find that Pr[X ≥ 40] ≈ 0.5866.
It follows that
Pr[X > 70 | X ≥ 40] ≈ 0.3932 / 0.5866 ≈ 0.6703
Answer:
answer b 8 months
Step-by-step explanation:
you can subtract 100 from 460, to get 360 which if you take 45/360 you would get 8, and have 100 dollars still that you took out
Answer:
$938.66
Step-by-step explanation:
Cheque = $341.79 + $17.96 =$359.75
<u>Cash</u>
Paper Currency:
=(35 X $1)+(17 X $5)+(44 X $10)
= 35+85+440
=$560
Coins
=(54 X $0.25)+(36 X $0.10)+ (32 X $0.05) + (21 X $0.01)
=13.5+3.6+1.6+0.21
=$18.91
Total Cash Deposit = Paper Currency + Coins
=$560+18.91
=$578.91
Therefore, Jacob's Total Deposit
= Total Cheque Deposit+ Total Cash Deposit
=$359.75+578.91
=$938.66
I think the answer to this problem would be C. 2x+8