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Sedbober [7]
3 years ago
6

EXPERTS/ACE/GENIUSES PLZ HELP

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
6 0
Sqrt(144) = 12
 so that is the rational number
 Answer is C

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1. Which inequality is true?<br>A.6 π &gt; 18<br>B.6 π &lt; 18<br>C.6 π = 18<br>D.18 &gt; 6 π<br>​
lilavasa [31]

Answer:

a

Step-by-step explanation:

a is the answer ..........

7 0
3 years ago
Which ordered pair is a solution of the equation y = -5x + 4
arsen [322]

D. (5,-21) would be your answer

8 0
3 years ago
Need help I don’t know what he did wrong
Naddik [55]

Answer:

6-2x+5+4x

Group the similar numbers

2x+11

Step-by-step explanation:

Tyler multiplied the numbers when he should've have grouped the similar numbers together

5 0
3 years ago
Explain: What is the solution to this system of equations? <br><br> 2x+y=20 <br> 6x-5y=12
bazaltina [42]

Answer:

solution set is (x,y) = (7,6)

Step-by-step explanation:

solving by substitution method

2x +y=20--------------1

6x-5y=12---------------2

from equation 1, solve for y

2x+y=20

y= 20-2x------equation 3

adding value of y in equation 2

6x-5y=12

6x-5(20-2x)=12

6x-100+10x=12

16x= 12+100

16x= 112

x= 112/16

x=7

adding value of x in equation 3

y= 20-2x

y= 20- 2(7)

y=20-14

y=6

so solution set (x,y) = (7,6)

3 0
3 years ago
A rancher wants to fence in an area of 1500000 square feet in a rectangular field and then divide it in half with a fence down t
VLD [36.1K]

Answer:

6000 ft

Step-by-step explanation:

Let length of rectangular field=x

Breadth of rectangular field=y

Area of rectangular field=1500000 square ft

Area of rectangular field=l\times b

Area of rectangular field=x\time y

1500000=xy

y=\frac{1500000}{x}

Fencing used ,P(x)=x+x+y+y+y=2x+3y

Substitute the value of y

P(x)=2x+3(\frac{1500000}{x})

P(x)=2x+\frac{4500000}{x}

Differentiate w.r.t x

P'(x)=2-\frac{4500000}{x^2}

Using formula:\frac{dx^n}{dx}=nx^{n-1}

P'(x)=0

2-\frac{4500000}{x^2}=0

\frac{4500000}{x^2}=2

x^2=\frac{4500000}{2}=2250000

x=\sqrt{2250000}=1500

It is always positive because length is always positive.

Again differentiate w.r.t x

P''(x)=\frac{9000000}{x^3}

Substitute x=1500

P''(1500)=\frac{9000000}{(1500)^3}>0

Hence, fencing is minimum at x=1 500

Substitute x=1 500

y=\frac{1500000}{1500}=1000

Length of rectangular field=1500 ft

Breadth of rectangular field=1000 ft

Substitute the values

Shortest length of fence used=2(1500)+3(1000)=6000 ft

Hence, the shortest length of fence that the rancher can used=6000 ft

3 0
4 years ago
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