115*20=2300.
50*5=250
First mechanic 20 hours
Second mechanic 5 hours
<h3>
The probability of selecting a random student who is enrolled in both the courses is 0.280.</h3>
Step-by-step explanation:
Here, the total number of freshman in the university = 500
The number of students enrolled in Economics = n(E) = 323
The number of students enrolled in Mathematics = n(M) = 205
The number of students enrolled in Both Economics and math
= n(E∩M ) = 140
Let F : Event of selecting a student who is enrolled in both the courses
So, from the given data:
So, the probability of selecting a random students who is enrolled in both the courses is 
Answer:
x= 3(3 +D)/ D - k
Step-by-step explanation:
move all terms to the left side and set equal to zero. Then set each factor equal to zero.
The probability of landing on the 4 spinners divided into four equal parts will be P=25%
<h3>What is probability? </h3>
Probability is defined as the ratio of the number of favorable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.
Here the spinner is divided into four parts of the colours green, red, yellow, and blue.So the number of the sample variable are:-
P(S)=[red,green,yellow,blue]=[4]
The favourable outcome is given as:-
F[s]=[1]
So the probability will be given by:-
P={1}÷{4}=0.25=0.25x 100=25\%
Hence the probability of landing on the 4 spinners divided into four equal parts will be P=25%
To know more about probability follow
brainly.com/question/24756209
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