Answer:
Mailing preparation takes 38.29 min max time to prepare the mails.
Step-by-step explanation:
Given:
Mean:35 min
standard deviation:2 min
and 95% confidence interval.
To Find:
In normal distribution mailing preparation time taken less than.
i.eP(t<x)=?
Solution:
Here t -time and x -required time
mean time 35 min
5 % will not have true mean value . with 95 % confidence.
Question is asked as ,preparation takes less than time means what is max time that preparation will take to prepare mails.
No mail take more time than that time .
by Z-score or by confidence interval is
Z=(X-mean)/standard deviation.
Z=1.96 at 95 % confidence interval.
1.96=(X-35)/2
3.92=(x-35)
X=38.29 min
or
Confidence interval =35±Z*standard deviation
=35±1.96*2
=35±3.92
=38.29 or 31.71 min
But we require the max time i.e 38.29 min
And by observation we can also conclude the max time from options as 38.29 min.
Answer:
5/32
Step-by-step explanation:
Since 5/8 x 1/4 = 5/32, that is the answer.
Key Note: When you get this type of question, multiply the second umber by the first.
There are 74.227 milliliters of acid in the solution.
Explanation:
- The total amount of liquid is 373 milliliters. This is both the acid and water combined i.e amount of liquid + amount of acid = 373 milliliters
- If 19.9% of this is acid it means 19.9% of the the entire 373 milliliters is acid. So we calculate how much 19.9% of 373 milliliters is.
- 19.9% of 373 milliliters = 0.199 × 373 = 74.227 milliliters. So 74.227 milliliters of the entire solution is acid.
Answer:
What kind of problem? Multiplication? Division? What?
Step-by-step explanation:
Given the amount of water needed to fill the cement dam and the water pump rate, the time needed to fill the dam is 400 minutes or 6hours 40minutes.
Option B)6h 40min is the correct answer.
<h3>How long does it take to fill the dam?</h3>
Given that;
- Amount of water needed to fill the dam A = 30000 litres
- Pump rate r = 75 litres per minute
- Time needed to fill the dam T = ?
To determine how long it take to fill the dam, we say;
Time need = Amount of water needed ÷ Pump rate
T = A ÷ r
T = 30000 litres ÷ 75 litres/minute
T = 400 minutes
Note that; 60min = 1hrs
Hence,
T = 6hours 40minutes
Given the amount of water needed to fill the cement dam and the water pump rate, the time needed to fill the dam is 400 minutes or 6hours 40minutes.
Option B)6h 40min is the correct answer.
Learn more word problems here: brainly.com/question/2610134
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