If you roll a six-sided die, what is the probability of rolling a number greater than 2?
2 answers:
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12x=4(x+5) (multiplying 4 by each argument in the parenhesis)
12x=4x+20 /-4x both sides
8x=20 /:8 divide both sides by 8
15x-3(3x+4)=6 (-3 times each argument in the parenthesis)
15x-9x-12=6
6x-12=6 /+12 both sides
6x=18 /:6 divide both sides by 6
x=3
3x-5x+10=36
-2x+10=36 /-10 both sides
-2x=26 /:(-2) divide both sides by -2
x=-13
2(x+3)=x+10
2x+6=x+10 /-x
x+6=10 /-6
x=4
12x=4x+20 /-4x both sides
8x=20 /:8 divide both sides by 8
15x-3(3x+4)=6 (-3 times each argument in the parenthesis)
15x-9x-12=6
6x-12=6 /+12 both sides
6x=18 /:6 divide both sides by 6
x=3
3x-5x+10=36
-2x+10=36 /-10 both sides
-2x=26 /:(-2) divide both sides by -2
x=-13
2(x+3)=x+10
2x+6=x+10 /-x
x+6=10 /-6
x=4