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saw5 [17]
3 years ago
13

For this data set, the least squares regression line is Y = 31.72 + 0.62X, where X represents the final exam score as a percent,

and Y represents the predicted course grade as a percent. Using the given equation of the regression line, what is the predicted course grade of a student who earns 85% on the final exam?
Mathematics
1 answer:
emmasim [6.3K]3 years ago
6 0

Answer:

  84.42

Step-by-step explanation:

Put the given value where X is, and do the arithmetic.

  Y = 31.72 + 0.62(85) = 31.72 +52.7 = 84.42

The predicted course grade is 84.42.

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Which inequality represents the graph
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Answer:

z≥-10

Step-by-step explanation

it just is, trust.

7 0
3 years ago
Mr. West is standing on a cliff that is 25 1/5meters above the surface of the ocean. He spots a dolphin that is 2 3/5 meters und
zhenek [66]

Answer:

Total distance from Mr. West to dolphin =27\frac{4}{5}\ meters

Step-by-step explanation:

Height of cliff on which Mr. West is standing above the surface of ocean =25 \frac{1}{5} \ meters

Mr. West spot the dolphin under the water at a depth of =  2\frac{3}{5} \ meters

∴ Total distance from Mr. West to dolphin=(25 \frac{1}{5}+2\frac{3}{5})\ meters

Adding mixed numbers

(25 \frac{1}{5}+2\frac{3}{5})

Adding whole numbers first.

=25+2+\frac{1}{5}+\frac{3}{5}\\=27+\frac{1}{5}+\frac{3}{5}

Adding fractions by taking LCD.

=27+\frac{1+3}{5}\\=27+\frac{4}{5}\\=27\frac{4}{5}\ meters

5 0
3 years ago
30 ounces is how many pounds
Effectus [21]

the answer is 1.875 pounds

5 0
3 years ago
The curves y = √x and y=(2-x) and the Cartesian axes form two distinct regions in the first quadrant. Find the volumes of rotati
makkiz [27]

Answer:

Step-by-step explanation:

If you graph there would be two different regions. The first one would be

y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\

And the second one would be

y = 2-x \,\,\,\,\,,  1 \leq x \leq 2.

If you rotate the first region around the "y" axis you get that

{\displaystyle A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51 }

And if you rotate the second region around the "y" axis you get that

{\displaystyle A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188 }

And the sum would be  2.51+4.188 = 6.698

If you revolve just the outer curve you get

If you rotate the first  region around the x axis you get that

{\displaystyle A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708 }

And if you rotate the second region around the x axis you get that

{\displaystyle A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472 }

And the sum would be 1.5708+1.0472 = 2.618

7 0
3 years ago
2. On Monday, I bought 3 dogs and 5 cats for a total cost of $8.25. On Tuesday, I bought 3 dogs and 6 cats for a total cost of $
Ratling [72]
I don’t know if you need to round, but you can do so on the answer for mondays if necessary

On Monday, the animals cost $1.03125.
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