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2 years ago

Given: ABCD is a ∥-gram; DE ∩ AB =F Prove: △ADF∼△CDE

Mathematics

1 answer:

Vedmedyk [2.9K]2 years ago

5 0

Answer:

By AA similarity

Step-by-step explanation:

We have been given that ABCD is a parallelogram

So, by the property of parallelogram AB ||CD and FD is cutting the line BC

Hence, FD is transverse line. In transverse line alternate angles are equal.

Therefore, ∠AFD=∠EDC (alternate interior angles)

And ∠FAD=∠ECD (opposite angles in parallelogram)

Therefore, by AA similarity △ADF∼△CDE

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Given

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