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3 years ago

Given: ABCD is a ∥-gram; DE ∩ AB =F Prove: △ADF∼△CDE

Mathematics

1 answer:

Vedmedyk [2.9K]3 years ago

5 0

Answer:

By AA similarity

Step-by-step explanation:

We have been given that ABCD is a parallelogram

So, by the property of parallelogram AB ||CD and FD is cutting the line BC

Hence, FD is transverse line. In transverse line alternate angles are equal.

Therefore, ∠AFD=∠EDC (alternate interior angles)

And ∠FAD=∠ECD (opposite angles in parallelogram)

Therefore, by AA similarity △ADF∼△CDE

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xenn [34]

Answer:

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Step-by-step explanation:

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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Marina CMI [18]

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3 years ago

Whatas the answer to 12.6+4m=9.6+8m

SVEN [57.7K]

Answer:

$\large\boxed{m=\dfrac{3}{4}=0.75}$

Step-by-step explanation:

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3 years ago

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Molodets [167]

Answer:

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3 years ago