All categories

3 years ago

Reflect -4,3 over the x-axis what is it

Mathematics

1 answer:

jasenka [17]3 years ago

6 0

Answer:

-4,-3

Step-by-step explanation:

I think thats right! If not, let me know.

You might be interested in

Is 6 3/5 greater than 1 1/3 or least than

Aliun [14]

Answer:

6 3/5 is greater then 1 1/3

Step-by-step explanation:

Ok sooo 6 is greater the 1 so yeah.

4 0

3 years ago

Read 2 more answers

Which of the following expressions is closest in value to 1?

xenn [34]

The correct answer is obviously C because 99/100 equals 99.99 which is closest to 1 Hope this helps! :D

4 0

4 years ago

Read 2 more answers

Solve the given initial-value problem. the de is of the form dy dx = f(ax + by + c), which is given in (5) of section 2.5. dy dx

shutvik [7]

$\dfrac{\mathrm dy}{\mathrm dx}=\cos(x+y)$

Let $v=x+y$ , so that $\dfrac{\mathrm dv}{\mathrm dx}-1=\dfrac{\mathrm dy}{\mathrm dx}$ :

$\dfrac{\mathrm dv}{\mathrm dx}=\cos v+1$

Now the ODE is separable, and we have

$\dfrac{\mathrm dv}{1+\cos v}=\mathrm dx$

Integrating both sides gives

$\displaystyle\int\frac{\mathrm dv}{1+\cos v}=\int\mathrm dx$

For the integral on the left, rewrite the integrand as

$\dfrac1{1+\cos v}\cdot\dfrac{1-\cos v}{1-\cos v}=\dfrac{1-\cos v}{1-\cos^2v}=\csc^2v-\csc v\cot v$

Then

$\displaystyle\int\frac{\mathrm dv}{1+\cos v}=-\cot v+\csc v+C$

and so

$\csc v-\cot v=x+C$

$\csc(x+y)-\cot(x+y)=x+C$

Given that $y(0)=\dfrac\pi2$ , we find

$\csc\left(0+\dfrac\pi2\right)-\cot\left(0+\dfrac\pi2\right)=0+C\implies C=1$

so that the particular solution to this IVP is

$\csc(x+y)-\cot(x+y)=x+1$

5 0

3 years ago

What is the circumference of the circle?

VashaNatasha [74]

What is the circumference of the circle?

answer: D) 69.08

explanation:

7 0

3 years ago

Read 2 more answers

Question 5

SVETLANKA909090 [29]

I have to go see my dog in the hospital today

8 0

3 years ago