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4 years ago

Which parts of the amino acids x and y are involved in the formation of a peptide bond?

Biology

2 answers:

NeTakaya4 years ago

6 0

Answer:

Carboxyl group and amino group.

Explanation:

Amino acids have three parts which are the carboxyl group, amino group and the side chain. When forming a peptide bond, the carboxyl group of one amino acid forms bonds with the amino group of the other one to form the peptide bonds between them.

I hope this answer helps.

kirill115 [55]4 years ago

5 0

Answer:

The carboxyl group of x and amino group of Y

Explanation:

An amino acid is made up of a carboxyl (-COOH) functional group, an amino (-NH2) functional group and a side chain (R group) . In the joining of two amino acid molecules, a chemical bond called the peptide bond is formed. The peptide bond is formed by the chemical a reaction between the acid carboxyl group (-COOH) of amino acid X and the amino group (-NH2) of amino acid Y. This reaction is referred to a condensation reaction as one molecule of water is lost in the reaction.

The continuous linkage and formation of peptide bonds between amino acids result to the formation of a polypeptide chain.

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If an entire tiger population disappears due to disease. What type of<br> limiting factor is this?

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3 years ago

How does the process of cytokinesis differ from the process of mitosis?

hram777 [196]

Answer:

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3 years ago

Joyce is planting tulips in her garden, and she has 5 red bulbs and 5 white bulbs to plant in one row. What is the probability t

Stolb23 [73]

Answer:

$\frac{1}{126}$ or 0.0079.

Explanation:

Joyce is planting tulips in her garden.

Number of red (R) bulbs = 5

Number of white (W) bulbs = 5

Total number of ways to plant 10 bulbs in one row is

$\text{Total ways}=\frac{10!}{5!5!}$

$\text{Total ways}=\frac{10\times 9\times 8\times 7\times 6\times 5!}{5\times 4\times 3\times 2\times 1\times 5!}$

Cancel out common factors.

$\text{Total ways}=252$

It is given that she randomly plants the bulbs so that all 5 red bulbs are next to each other and all 5 white bulbs are next to each other.

Required outcomes are

RRRRRWWWWW and WWWWWRRRRR

$\text{Required outcomes}=2$

Formula for probability:

$Probability=\frac{\text{Required outcomes}}{\text{Total ways}}$

$Probability=\frac{2}{252}$

$Probability=\frac{1}{126}$

$Probability\approx 0.0079$

Therefore the required probability is $\frac{1}{126}$ or 0.0079.

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3 years ago

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3 years ago

Activity 12-5: A Dihybrid Punnett Square. Consider your answers in the previous question. In a separate piece of paper, solve th

GaryK [48]

Answer:

See the answer below

Explanation:

For each heterozygous parent with the genotype BbRr, the possible gametes are: BR, Br, bR, and br. A set of these gametes from one of the parents will be lined up along the top of the Punnet's square while another set from the other parent will be lined up along the side of the square.

The result is shown in the attached image.

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3 years ago