Which of the following infectious agents cannot live outside of a human body for extended periods of time?

What does the Miller-Urey experiment tell us about the origin of life?

aivan3 [116]

Answer:

B inorganic materials can form organic molecules under the right conditions

7 0

2 years ago

E. within this feedback loop, do the signals from the response change in magnitude (lesser, greater) or direction (positive, neg

zepelin [54]

Answer

the answer is lesser i did a test on it

7 0

2 years ago

Bagaimana adaptasi tubuh manusia terhadap kadar oksigen yang rendah dipegunungan

never [62]

<span>Persentase oksigen di udara di dua mil (3,2 km.) Pada dasarnya sama dengan di permukaan laut (21%). Namun, tekanan udara adalah 30% lebih rendah pada ketinggian yang lebih tinggi karena fakta bahwa atmosfer kurang padat - yaitu, molekul udara yang jauh apart.When kita menghirup udara di permukaan laut, tekanan atmosfer sekitar 14,7 pounds per square inch (1,04 kg. per cm.2)

(i speak indoinision to)
</span>

7 0

3 years ago

(b) Describe how a student could test cow's milk to show whether it contains protein

marin [14]

Milk contains a lot of proteins in them it contains calcium protein potassium iodine. Phosphorus. It also contains vitamins b1 and b12.

5 0

3 years ago

Suppose that one of the normal children from Part B and one of the albino children from Part C become the parents of eight offsp

Aleks [24]

Full question from alternative source:

Albinism in humans is inherited as a simple recessive trait. for the following families, determine the most likely genotypes of the parents

Part A

Two normal parents have five children, four normal and one albino. What are the most likely genotypes of the parents?

Part B

A normal male and an albino female have six children, all normal. What is the most likely genotypes of the parents?

Part C

A normal male and an albino female have six children, three normal and three albino. What are the most likely genotypes of the parents?

Part D

Suppose that one of the normal children from Part B and one of the albino children from Part C become the parents of 8 offspring. What would be the expected number of normal and albino offspring?

Answer:

Part A - both heterozygous for the trait (Aa)

Part B - female aa, male likely AA

Part C - female aa, male Aa

Part D - 4 normal, 4 albino (50:50)

Explanation:

Part A

We are told that albinism is a recessive trait. Lets call it a and the normal allele A. Since neither of the parents have it, that must mean they each possess at least one copy of the dominant allele (either AA or Aa). Most of their children are normal, but 1 is albino. The albino child must have inherited two copies of the a allele, one from each parent. This means each parent must possess an a allele and must both be Aa.

Part B

Since the trait is recessive, we already know that the albino female must have the genotype aa. If her husband in homozygous normal (AA), all their children will be heterozygous (Aa), and therefore normal, which is the case in this cross. Therefore aa and AA are the most likely genotypes. However, it is still possible that the male has the genotype Aa. This would mean they had a 50:50 chance of producing an albino offspring. We know they have six normal children, so this is unlikely.

Part C

Since the trait is recessive, we know the female has the genotype aa. Unlike the last family, this family has some albino children. This means that the husband must be a carrier of the trait, but he is unaffected, so must be Aa.

As described in part B, if he is Aa and she is aa, they will have 50:50 normal:albino children. This is the ratio in this family.

Part D

The normal children from Part B are all heterozygous for the trait (Aa), inheriting one normal allele from their father, and one albino allele from their mother. The albino children from part C are all aa. Therefore, the cross is Aa x aa. We can draw a punnett square:

Aa

A a

a Aa aa

aa a Aa aa

Half the children have the genotype Aa, and half have the genotype aa. That means half will be normal and half will be albino. Therefore, 4 normal, 4 albino.

4 0

3 years ago